Sir Mike Ambrose is the author of the question.
Let beta be x.
x = (½*atan(5/4))
Let alpha be y.
y = (½*atan(4/5))°
Therefore;
Area blue exactly in cm² decimal is;
Area triangle with hei...
Let the two equal red lengths of the triangle, ABC be 1 unit.
Therefore;
AB = CE = 1 unit.
a = 180-100-20
a = 60°
(b/sin100) = (1/sin20)
b = 2.8793852416 units.
b is BC.
c = 2.8793852416-1
c = 1...
Sir Mike Ambrose is the author of the question.
Calculating a.
½((0, 6√(3)) (-3, 3√(3)) (a, (16a/3)) (0, 6√(3))) = ¼(9+20√(3))
Therefore;
a = x = ½√(3) unit
y = 16a/3 = (16/3)(√(3)/2)
y = ⅓(8√(3))...
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a² = (2+1)²+2²
a² = 9+4
a = √(13) units.
Where a is blue length + red length.
b² = 1+2²
b = √(5) units.
tanc = 2/3
c = atan(2/3)°
tand = 2/1
d = atan(2)°
e = 90-d
e = 90-atan(2)
e = atan(½)°
f...
Notice.
Radius of the semi circle is 5 cm.
Let the width of the blue rectangle be a.
Therefore;
Blue rectangle length is 2a.
b² = a²+a²
b = √(2a²)
b = √(2)a
c = ½(b)
c = ½(√(2)a)...
Calculating the length and width of the rectangle.
Let the length be a.
Let the width be b.
Notice;
½(a) = b
Or
2b = a
It implies;
b²+b² = 4²
2b² = 16
b² = 8
b = 2√(2) cm.
The...
Let the base of the triangle be 1 unit.
a = 20+100 = 120°
b = 10+10 = 20°
c = 190-a-b
c = 180-120-20
c = 40°
It implies;
(1/sin120) = (d/sin40)
d = 0.742227199 units.
e = 180-10-20
e = 180-30
e...
Sir Mike Ambrose is the author of the question.
Radius, r of the inscribed circle is;
r = (3-√(3)) cm
Therefore;
Area purple exactly in square cm is;
Area trapezium with parallel sides (3-√(3)) c...
Shaded area is;
Area trapezoid with parallel sides 58 cm and 28 cm, and height 30 cm - Area trapezoid with parallel sides 9 cm and 30 cm, and height 28 cm - Area triangle with height 12 cm and base...
