By OnlineEdumath   |  29th March, 2024
Calculating Grey Area. a² = 5²+2² a = √(29) m. tanb = 5/2 b = atan(5/2)° c = (90+b)° c = (90+atan(5/2))° d² =√(29)²+4²-2*4√(29)cos(90+atan(5/2)) d = 9.2195444573 m. d is the diagonal of the rect...
By OnlineEdumath   |  29th March, 2024
Let a be the side length of the purple inscribed square. b² = 4 b = 2 cm. b is the side length of the green inscribed square. c² = 1 c = 1 cm. c is the side length of the yellow ascribed square....
By OnlineEdumath   |  29th March, 2024
Calculating angle x. Let AB be 1 unit. a = 9-20  a = 70° a is angle ABH. b = 180-10-70 b = 100° (c/sin70) = (1/sin100) c = 0.9541888941 units. (d/sin10) = (1/sin100) d = 0.1763269807 units. si...
By OnlineEdumath   |  29th March, 2024
Let BC be 1 unit. a = ½(180-45) a = ½(135) a = 67.5° a is angle ABC = angle ACB. (1/sin45) = (b/sin67.5) b = 1.3065629649 units. b is AB. c = 180-45-67.5 c = 67.5° c is angle BEC....
By OnlineEdumath   |  28th March, 2024
Let the side length of the regular pentagon be 1 unit. a = ⅕(180(5-2)) a = 108° a is the single interior angle of the regular pentagon. b² = 2-2cos108 b = 1.6180339887 units. c = ½(180-108) c = 36...
By OnlineEdumath   |  28th March, 2024
Notice! Radius of the ascribed semi circle is 6 cm. It implies; Radius, a of the inscribed bigger circle is; a = ½(6) a = 3 cm. Calculating b, radius of the smaller inscribed circle. c = (6-b) c...
By OnlineEdumath   |  28th March, 2024
Calculating the area of the inscribed rectangle. Let the length and width of the inscribed rectangle be x and y respectively. Therefore, observing similar plane shapes (right-angled) side length ra...
By OnlineEdumath   |  28th March, 2024
Calculating area of the inscribed blue square. Let the inscribed blue square side be x. a² = 2x² a = √(2)x units. a is the diagonal of the inscribed blue square. x² = 2b² b² = x²/2 b = ½√(2)x uni...
By OnlineEdumath   |  28th March, 2024
Notice! AQ = 6 cm. a² = 6²+3²-2*6*3cos108 108° is the single interior angle of the regular pentagon. a = 7.4916361229 cm. a is AP. cosb = 6/7.4916361229 b = acos(6/7.4916361229)° b is angle PAQ....
By OnlineEdumath   |  27th March, 2024
(4+5+3)² = 2a² a² = 72 a = 6√(2) cm. a is the congruent adjacent sides of the right-angled triangle. b² = √(72)²+3²-2*√(72)*3cos45 b² = 81-36 b = √(45) b = 3√(5) cm. (3√(5)/sin45) = (3/sinc) c = 1...
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