Notice!
AQ = 6 cm.
a² = 6²+3²-2*6*3cos108
108° is the single interior angle of the regular pentagon.
a = 7.4916361229 cm.
a is AP.
cosb = 6/7.4916361229
b = acos(6/7.4916361229)°
b is angle PAQ.
Therefore, area triangle PAQ (area blue) is;
0.5*6*7.4916361229sin(acos(6/7.4916361229))
= 13.4581390311 cm²
≈ 13.46 cm² to 2 decimal places.
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