Let AB = a.
Let BE = b.
It implies;
2a+b = 392
b = 392-2a
BC = ½(b-70)
BC = ½(392-2a-70)
BC = ½(322-2a)
Therefore;
BC = DE = 161-a
c = ½(70)+161-a
c = 196-a
Where c is half BE.
d² = a²-(196-a)²...
a² = 6²+12²
a = 6√(5) cm.
Where a is CE = EF.
b² = 2(a²)
b² = 2(6√(5))²
b² = 360
b = 6√(10) cm.
Where b is CF.
Angle DCE = atan(½)°
Angle ECF = 45°
Angle FCM = 90-45-atan(½)
Angle FCM = 18.43494...
Let CE = 1 unit.
(1/sin20) = (a/sin40)
a = 1.87938524157 units.
Where a is AE.
Notice;
b = a-1
b = 1.87938524157-1
b = 0.87938524157 units.
Where b is AD.
Angle AEC = 180-20+40
An...
a = ½(180-150)
a = 15°
b = 60-15
b = 45°
c² = 2(6²)
c = 6√(2) cm.
d² = 72+12²-144√(2)cos135
d= 6√(10) cm.
(6√(10)/sin135) = (12/sine)
e = 26.56505117708°
f = 180-135-26.56505117708
f = 18.4349...
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Destiny (year 10), Oghenevwarhe (year 8) and Ogheneruona (year 10).
Educators:
Mr. O...
(6/sin(180-45-atan(2))) = (a/sin45)
a = 4.472135955 cm.
b = √(12²+6²)+a
b = 17.88854382 cm.
c² = 4.472135955²+6²-12*4.472135955cos(180-atan2)
c = 8.94427191 cm.
Where c is CF.
(8.94427191/sin(180...
Area Blue Triangle is;
½*10*10sin(90-2tan(½))
= 50sin(90-2tan(½))
= 50(⅗)
= 30 cm²
tan60 = a/5
a = 5√(3) cm.
Where a is AD.
b = ½(a)
b = ½(5√(3)) cm
c = atan((½(5√(3))/5)
c = atan(½√(3))
Where c is angle AGB
d = atan(5√(3)/5)
d = atan(√(3))
Where d is angle CAG.
e = 180-c-d
e...
Screenshot of today's teaching and learning activities with some of our super, smart and clever learners;
Ogheneruona (year 10), Manasseh (year 8) and Oghenemano (year 8).
Educators;
Mr. Ovo, Mr. Da...
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