Calculating R, radius of the ascribed circle.
a² = 4.5²+2.9²-2*4.5*2.9cos60.8
a = 3.9908473908 units.
(3.9908473908/sin60.8) = (4.5/sinb)
b = 79.8304370724°
c = ½(4.5)
c = 2.25 units.
Therefore,...
Calculating area red.
tana = 3/5
a = atan(3/5)°
b = 2a
b = 2atan(3/5)°
tanc = 5/3
c = atan(5/3)°
d = 2c
d = 2atan(5/3)°
Therefore, red area is;
2(area circle with radius 5 units) - 4(area quar...
Let a be the side of the inscribed square.
24² = a²+(2a)²
576 = a²+4a²
576 = 5a²
a = √(576/5)
a = 10.733126292 cm.
b = ½(24-10.733126292)
b = 6.633436854 cm.
b = AM = DR.
c = atan(6.633436854/(...
tana = 3/4
a = atan(3/4)°
b = atan(4/3)°
sin(atan(3/4)) = c/4
c = 2.4 units.
Area Blue is;
Area semi circle with radius 2.5 units - Area sector with radius 2 units and angle (180-2atan(3/4))° +...
tan30 = 4/a
a = 4√(3) units.
sin30 = 4/b
b = 8 units.
c = b-2
c = 8-2
c = 6 units.
Therefore, Area Blue is;
Area semi circle with radius 4 units - Area sector with radius 2√(3) units a...
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever.
Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
Calculating x (length BE).
sin60 = a/8
a = 4√(3) units.
a is DE.
cos60 = b/8
b = 4 units.
b is AD
c² = 2²+(2√(3))²
c = √(4+12)
c = 4 units.
d = (4+x) units.
Therefore, length x (BE) is;
Observi...
a² = 6²+8²-2*6*8cos30
a = 4.10628314132 cm.
a = DE.
(4.10628314132/sin30) = (8/sinb)
b = 103.06431342951°
b = Angle ADE.
Angle AED = 180-30-103.06431342951
= 46.93568657049°
tan30 = c/6
c = 3.46...
Notice, radius of the three congruent circles is 7 cm each.
sin60 = a/14
a = 7√(3) cm.
a = 12.124355653 cm.
b = a+7+7
b = (7√(3)+14) cm.
b = 26.124355653 cm.
b is the length of the rectangle.
tan...
a = ½(4+6)
a = 5 cm.
a is the radius of the ascribed semi circle.
Let b be the radius of the blue inscribed semi circle.
c = 5-4
c = 1 cm.
It implies;
b²+c² = d²
d² = b²+1²
d = √(...
