Calculating x, angle ABD
a = ½(180-x)°
a is angle BAD.
It implies;
x, angle ABD is,
x+x+(a+39) = 180 (sum of the interior angles of the ascribed triangle)
2x+½(180-x) = 180-39
2x+½(180-x) = 141
4x+180-x = 282
3x = 282-180
3x = 102
x = 34°
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