a = 2*135
a = 270°
a is reflex angle BOE.
b = 360-a
b = 90°
b is angle BOE.
c² = 6²+2-2*6√(2)cos135
c = 7.0710678119 units.
c = 5√(2) units.
c is BE.
Notice!
Since angle BOE is 9...
Let a be the radius of the quarter circle.
b = (a-10) units.
b is the width of the inscribed rectangle.
c = (a-5) units.
c is the length of the inscribed rectangle.
Therefore;
a² = (a...
a = 2+2
a = 4 units.
b = a-½(2)
b = 4-1
b = 3 units.
c² = 2(3²)
c = √(18)
c = 3√(2) units.
d² = (3√(2))²+4²-2*3√(2)*4cos45
d = √(10) units.
d = 3.1622776602 units.
d is the radius...
Calculating area x.
Let the square side length be 2a.
b² = a²+(2a)²
b = √(5a²)
b = √(5)a units.
c² = 2a²
c = √(2)a units.
c is the side length of the inscribed regular triangle (equila...
Calculating angle x.
Let the base of the ascribed triangle be 1 unit.
a = 180-20-10-10-100
a = 180-140
a = 40°
(1/sin(100+10)) = (b/sin40)
b = 0.6840402867 units.
c = 180-100-20
c =...
Let the radius of the red circle be r.
Calculating r.
It will be;
√(13²-5²)=√((9+r)²-(9-r)²)+√((4+r)²-(4-r)²)
12=√(36r)+√(16r)
12=10√(r)
√(r)=1.2
r=1.44 unit.
Calculating angle PQR...
Let the required length be x.
Therefore, analysing the composite plane shape.
It implies, the required length, x will make a right-angled isosceles triangle with two radii length, 4 units eac...
Notice!
The composite plane shape consist of two congruent quarter circles with radius 2 units each.
a = 3-2
a = 1 unit.
cosb = 1/2
b = acos(½)°
b = 60°
Area green is;
2(area sector...
Calculating angle x.
Notice!
The inscribed triangle is isosceles.
Let the base be 1 unit.
It implies;
a = 180-80-40
a = 60°
(b/sin80) = (1/sin60)
b = 1.1371580426 units.
(1/sin...
Blue area is;
Area sector with radius 3√(2) unit and angle 30° - area isosceles triangle with two equal length 3√(2) unit and angle 30°.
= (30πx(3√(2))²÷360) - (0.5x(3√(2))²sin30)
= (18π)/12...
