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We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2255686

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255662

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Notice; The semi circle has inscribed quadrilateral which is a cyclic quadrilateral when the semi circle is made a complete circle considering it's diameter. Calculating Alpha. Let it be a. It implies; 60+b = 180 b = 120° Therefore; a+b = 180 a = 180-b Where b = 120°, and a is Alpha. It implies; a = 180-120 a (Alpha) = 60°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255632

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cos30 = r/(1-r) Where r is the radius of each of the three congruent inscribed circles. It implies; 2r = √(3) - √(3)r r = √(3)/(2+√(3)) r = (2√(3)-3)/(1) r = (2√(3)-3) unit. r = 0.46410161514 unit.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255511

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Area blue is; Area square with side 10 cm - Area triangle with height 5 cm and base 10 cm - Area triangle with height 10 cm and base (4.71404520791sin45) cm - Area triangle with height 5 cm and base (4.71404520791sin45) cm - Area triangle with height 5 cm and base (2.2360679775sin(atan(2))) cm = 10² - ½(10*5) -½(10*4.71404520791sin45) - ½(5*4.71404520791sin45) - ½(5*2.2360679775sin(atan(2))) = 100 - 25 - ⅓(50) - ⅓(25) - 5 = 70 - ⅓(50) - ⅓(25) = ⅓(210-75) = ⅓(135) cm² = 45 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255445

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Calculating r, radius of the Semi Circle. ½(π)r² = 338π r² = 676 r = 26 cm. a = ½(48) a = 24 cm. Calculating x. It implies; Observing Pythagoras Rule. 26² = 24²+x² x² = 676-576 x² = 100 x = 10 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255443

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a = ⅐*180(7-2) a = ⅐(180*5) a = ⅐(900)° a is the single interior angle of the regular heptagon. Calculating x and y. b = 360-2*⅐(900) b = (360/1)-(1800/7) b = ⅐(2520-1800) b = ⅐(720)° c = ½(b) c = ½*⅐*720 c = ⅐(360)° It implies; Angle x is; x = ⅐(900)-c x = ⅐(900)-⅐(360) x = ⅐(540)° Angle y is; y = 180-c y = (180/1)-(360/7) y = ⅐(1260-360) y = ⅐(900)°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255282

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a = 10+94 a = 104° a is angle BAC. b = 24+34 b = 58° b is angle ABC. Let AB = 1 unit. c = 180-58-104 c = 180-162 c = 18° c is angle ACB. It implies; (1/sin18) = (d/sin104) d = 3.1399429285 units. d is BC. e = 180-94-24 e = 108-118 e = 62° e is angle ADC. It implies; (1/sin62) = (f/sin94) f = 1.129811167 units. f is BD g² = 1.129811167²+3.1399429285²-2*1.129811167*3.1399429285cos34 g = 2.2920782452 units. g is CD. Calculating x, angle BCD. (2.292078245...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2255255

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a² = 6²+8² a = √(100) a = 10 cm. a is the hypotenuse of the ascribed right-angled triangle. Let b be the hypotenuse of the blue inscribed right -angled triangle. It implies, observing similar triangles ratio. 6 = 3 10 = b, cross multiply. 6b = 3*10 b = 5 cm. Let c be the base of the inscribed blue right-angled triangle. Calculating c. 5² = 3²+c² c = √(25-9) c = √(16)  c = 4 cm. Therefore, Area Blue is; ½*3*c = ½*3*4 = 6 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2254718

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b = 8-a  It implies; 27^(a)/3^(8-a) = 81 3^(3a) = 3^(8-a)*3⁴ 3a = 8-a+4 3a = 12-a 4a = 12 a = 3. Calculating b. b = 8-a And a = 3 b = 8-3 b = 5

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2254650

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a = 4+8  a = 12 cm. a is the radius of the quarter circle. tanb = 12/4 b = atan(3)° c = (60+atan(3))° (12/sin(60+atan(3))) = (4/sind) d = 14.4420678686° e = 180-60-atan(3)-d e = 120-atan(3)-14.4420678686 e = 33.9928809543° f = 90-e f = 90-33.9928809543 f = 56.0071190457° (12/sin(60+atan(3))) = (g/sin33.9928809543) g = 8.9669238624 cm. h² = 4²+12² h = √(16+144) h = √(160) h = 4√(10) cm. Therefore; Area Blue is; Area triangle with height 4√(10) cm and bas...
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