Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2248544

Let the square side be x. Calculating x. a = (5-½(x)) units. b = (5-x) units. It implies; 5² = (5-½(x))²+(5-x)² 25 = 25-5x+¼(x)²+25-10x+x² ¼(5x²)-15x+25 = 0 ¼(x²)-3x+5 = 0 x²-12x+20 = 0 Resolving the above quadratic equation. x²-10x-2x+20 = 0 x(x-10)-2(x-10) = 0 (x-2)(x-10) = 0 It implies; x ≠ 10 units. x = 2 units. Where x is the side length of the square. Therefore; Area square is; x² = 2² = 4 square units. = 4 m²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2246027

The side of area green, inscribed square is; Let it be x. Therefore; 1.11496246101x + 0.82101781219x = 27.3672604063 1.9359802732x = 27.3672604063 x = 14.1361256544 cm Therefore; Exact perimeter of green area in decimal cm is; 4(14.1361256544) = 56.5445026176 cm

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2244605

Let BC be 1 unit. a = 180-18-64 a = 180-82 a = 98° a is angle BDC (1/sin98) = (b/sin18) b = 0.3120538813 units. b is BD c = 180-4-18-64-46 c = 180-132 c = 48° c is angle BAC. (1/sin48) = (d/sin22) d = 0.5040828928 units. d is AB. e² = 0.5040828928²+0.3120538813²-2*0.5040828928*0.3120538813cos46 e = 0.3646042276 units. e is AD. (0.3646042276/sin46) = (0.3120538813/sinx) where x is the required angle (angle BAD) x = 38°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2244589

Let AC be 1 unit. Area smaller pentagon is; ½(5)*(1/(2tan(36))) = 1.72047740059 square units. a² = 1²+0.5²-cos108 a = 1.24860602048 units. Where a is CD. (1.24860602048/sin108) = (0.5/sinb) b = 22.38617755917° c = 108-22.38617755917 c = 85.61382244083° Calculating Area E. It is; 0.5*0.5*0.5*1.24860602048sin22.38617755917 = 0.05944103227 square units. (a) Area E ÷ Area Smaller Pentagon to 3 decimal places is; 0.05944103227 ÷ 1.72047740059 = 0.03454915028 ≈ 0.035 Calculating r, radius...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2243242

Area Blue is; Area trapezium with two parallel side 4 cm and 1 cm, and height 4 cm - Area semi circle with radius 2 cm. = ½*4(4+1) - ½(4π) = 10 - 2π = 2(5-π) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2242676

a = 180-12-2-46-8 a = 180-68 a = 112° a is angle ABC. Let AC be 1 unit. It implies; (1/sin112) = (b/sin14) b = 0.257447904 units. b is AB. c = 180-8-2 c = 170° c is angle ADC. It implies; (1/sin170) = (d/sin2) d = 0.2009781915 units. d is AD. e² = 0.2009781915²+0.257447904²-2*0.2009781915*0.257447904cos46 e = 0.1865112432 units. e is BD. (0.1865112432/sin46) = (0.2009781915/sinf) f = 50.8173805282° f is angle ABD. It implies; x (angle CBD) = a-f x = 112-50.8173805282 x = 61.1826194718°...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2241077

Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348134903121 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath Truly, we are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2241064

tana = 12/8 a = atan(3/2)° b = 180-a b = (180-atan(3/2))° (10/sin(180-atan(3/2))) = (4/sinc) c = 19.4400348282° d = 180-b-c d = 180-19.4400348282-(180-atan(3/2)) d = 36.8698976458° e = 90-d e = 90-36.8698976458 e = 53.1301023542° It implies, Area S (shaded area green) is; Area trapezoid with height 12 units, and parallel sides 4 units and 12 units respectively - Area triangle with height 10 units and base 4sin36.8698976458 units - Area sector with radius 10 units and angle 53.1301023542°...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2239203

Shaded area is; Area under the curve at points (-1, 0) and (7, 0) - Area triangle with height 4 unit and base 8 unit. = ⅓(208) - ½(4*8) = ⅓(160) space unit. Area S is; Area under the curve at points (-2, 0) and (7, 0) - Area triangle with height 4 unit and base 8 unit - Area triangle with height 1 unit and base (7/4) unit - Shaded area. = 72 - ½(4*8) - ½(1(7/4)) - ⅓(160) = (43/24) space unit. Area R is; Area triangle with height 4 unit and base 2 unit - Area triangle with height 1 unit...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2237207

Let the side of the regular hexagon be 1 unit. Therefore; Area blue is; 2(area triangle with height 1 unit and base (⅓√(3)) unit). = 2(½*1*(⅓√(3))) = ⅓√(3) space unit. Area orange is; Area triangle with height (3-√(3))/6 unit and base (√(3)-1) unit. = ½*(3-√(3))/6*(√(3)-1) = (2√(3)-3)/6 space unit. It implies; Area Blue ÷ Area Orange Exactly is; ⅓√(3) ÷ (2√(3)-3)/6 = 2√(3) ÷ (2√(3)-3) = (2√(3)*(2√(3)+3)) ÷ ((2√(3)-3)*(2√(3)+3)) = (12+6√(3)) ÷ (12-9) = 6(2+√(3)) ÷ 3 =...

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