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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2218108

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Let the side of the regular pentagon be 1 unit. Therefore; Area purple is; Area trapezium with two parallel side 0.07294901687 unit and 0.38196601125 unit, and height cos18 unit. = 0.5*cos18*(0.07294901687+0.38196601125) = 0.21632495093 space unit. Area yellow is; Area trapezium with two parallel side 0.27345747199 unit and 1 unit, and height 1 unit - Area triangle with height 0.27345747199 unit and base 0.198678483 unit. = (0.5*1*(0.27345747199+1)) - (0.5*0.27345747199*0.198678483) = 0.636...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2217048

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Let the side length of the regular heptagon be 1 unit. a = ⅐(180(7-2))  a = 128.5714285714° Where a is the single interior angle of the regular heptagon. b² = 2-2cos128.5714285714 b = 1.8019377358 units. c = ½(180-128.5714285714) c = 25.7142857143° d = 128.5714285714-25.7142857143 d = 102.8571428571° e² = 1.8019377358²+1-2*1.8019377358cos102.8571428571 e = 2.2469796037 units. Where e is r+q+p. (2.2469796037/sin102.8571428571) = (1/sinf) f = 25.7142857144° g = 180-25.7142857144-102.85714...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2216945

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a² = 8-8cos(360-90-108) a² = 8-8cos162 a = 3.9507533624 units. b = ½(180-162) b = 9° c = 90+9 c = 99° d² = 3.9507533624²+1-2*3.9507533624cos99 d = 4.2242774658 units. (4.2242774658/sin99) = (3.9507533624/sine) e = 67.4783733984° Calculating Alpha. Let it be f. f = 90-e f = 90-67.4783733984 f (Alpha) = 22.5216266016° f ≈ 22.52° to 2 decimal places. Calculate x. tan22.5216266016 = x/2 x = 2tan22.5216266016 x = 0.8293116961 units. x = 0.83 units to 2 decimal places.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2215031

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348134903121 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath Truly, we are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2214642

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Notice; Red circle and black circle are congruent, they have equal radius, 1 cm. Calculating Area Shaded. a = 60-45 a = 15° It implies; Area Shaded is; Area sector with radius 1 cm and angle 60° - Area triangle with base 1 cm and height sin60° + Area sector with radius 1 cm and angle 15° = (60π/360) - ½(sin60) + (15π/360) = (π/6)-¼(√(3))+(π/24) = (4π-6√(3)+π)/24 = (5π-6√(3))/24 cm² = 0.2214857676 cm²

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2213622

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Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online at affordable tuition.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2209645

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Let AB be x. Therefore BC = 2x. Calculating x. Yellow area + Area triangle with height 2x and base ½(3x)sin60 = Area trapezoid with two parallel side ½(3x) and 2x, and height ½(3√(3)x). Therefore; 30√(3)+¾*√(3)x² = (21√(3)x²)/8 30+¾x² = (21x²/8)  240+6x² = 21x² 15x² = 240 Therefore; x = 4 unit. Calculating Area Orange, exactly in square cm decimal form. It will be; Area trapezoid with two parallel side 4 unit and 6 unit, and height 6√(3) unit - Area triangle with height 6 unit and base 2...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2209118

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Area blue exactly in cm² decimal is; Area trapezoid with two parallel sides 12 unit and (12-16tan15) unit, and height 16 unit - Area triangle with height (12-16tan15) unit and base 4 unit - Area triangle with height and base 12 unit each - Area triangle with height 8√(2) unit and base (8-8tan15)sin45 unit. = ½*16(12+12-16tan15) - ½*4(12-16tan15) - ½(12²) - ½*8√(2)*(8-8tan15)sin45 = 157.702503369 - 15.4256258422 - 72 - 23.4256258422 = 46.8512516846 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2207657

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Notice; cos2x = 1-2(sinx)² --- (1). Substituting (1) in the given equation. ½(3-6(sinx)²+3)+4sinx+1 = 0 3-6(sinx)²+3+8sinx+2 = 0 6(sinx)²-8sinx-8 = 0 Calculating sinx. Let sinx be p. 6p²-8p-8 = 0 6p²-12p+4p-8 = 0 6p(p-2)+4(p-2) = 0 Therefore; p ≠ 2 p = -⅔ And p = sinx sinx = -⅔ Therefore; cosx = ⅓(√(5))  It implies; The exact value of Tanx is; tanx = sinx/cosx tanx = (-⅔)/(⅓(√(5)) tanx = (-2/√(5)) tanx = l-2/√(5)l tanx =  (2/√(5))

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2205999

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sinxcos60+sin60cosx-(cosxcos45+sinxsin45) = 0 0.5sinx+½(√(3)cosx)-½(√(2)cosx)-½(√(2)sinx) = 0 0.5sinx-½(√(2)sinx) = ½(√(2)cosx)-½(√(3)cosx) sinx(1-√(2)) = cosx(√(2)-√(3)) sinx = ((√(2)-√(3))cosx)/(1-√(2)) sinx = ((√(2)+2-√(3)-√(6))cosx)/-1 sinx = -(√(2)+2-√(3)-√(6))cosx sinx = (√(3)+√(6)-√(2)-2)cosx (sinx/cosx) = (√(3)+√(6)-√(2)-2) tanx = (√(3)+√(6)-√(2)-2) x = atan(√(3)+√(6)-√(2)-2)) x = 37.5° It implies; sinx = (√(3)+√(6)-√(2)-2)cos(37.5) sinx = (√(3...
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