Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2263785

Let the side of the regular pentagon be 1 unit. Notice; The regular pentagon side is equal the regular heptagon side. a = ⅐(180*5) a = ⅐(900)°, the single interior angle of the regular heptagon. b = 2a b = ⅐(450)° tan(⅐(450)) = c/0.5 c = 1.03826069829 units. cos(⅐(450)) = 0.5/d d = 1.15238243548 units. Where d is the radius of the ascribed circle. e = 180-⅐(900) e = ⅐(360)° tan18 = 0.5/f f = 1.53884176859 units. g² = 1.15238243548²-0.5² g = 1.03826069828 units. h = f-g h = 0.5005810...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2263515

It implies; tan(0.5acos(3/5)) = r/3 Where r is the radius of the inscribed semi circle. r = 3tan(0.5acos(3/5)) r = 1.5 units. r = 1½ units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2263104

Let the side length of the square be 2 unit. Therefore area ABD (equilateral triangle) is; Area triangle with height 2 unit and base (2sin60) unit. = ½*2*2sin60 = √(3) square unit. Area purple is; Area triangle with height 2√(5-2√(3)) unit and base (√(3)/3sin(atan(⅓(2+√(3)))))sin(atan(⅓(2+√(3)))+atan(½(√(3)+1))). = ½(2√(5-2√(3)))(√(3)/3sin(atan(⅓(2+√(3)))))sin(atan(⅓(2+√(3)))+atan(½(√(3)+1))) = ½*(2√(5-2√(3)))(√(3)/3sin(atan(⅓(2+√(3)))))sin(105) = (√(5-2√(3))*√(3)*sin105)/(3sin(atan(⅓(2+√(3...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2263025

Let BD = y units. Let angle BAD = a It implies; tana = y/6 --- (1). tan(a+45) = (y+10)/6 (tana+tan45)/(1-tanatan45) = (y+10)/6 --- (2) Therefore, Substituting (1) in (2). Notice. tan45 = 1 unit. It implies; ((y/6)+1)/(1-(y/6)) = (y+10)/6 ((y+6)/6)/((6-y)/6) = (y+10)/6 (6+y)/(6-y) = (y+10)/6 Cross Multiply. 36+6y = 6y+60-y²-10y y²+10y-24 = 0 Resolving the above quadratic equation to get y. y²+12y-2y-24 = 0 y(y+12)-2(y+12) = 0 (y-2)(y+12) = 0 It implies; y ≠ -12 y = 2 units. y is BD...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2262927

a = 3x+x a = 4x a is the square side. it implies; Area Square is; a² = (4x)² = 16x² square units. Calculating Shaded Area. b = 45° tanc = (4x/3x) c = atan(4/3)° d = 180-b-c d = (180-45-atan(4/3))° Therefore; (4x/sin(180-45-atan(4/3))) = (e/sin(atan(4/3)) e = 3.2324881426x units. It implies; Shaded Area is; 0.5*3.2324881426x*4xsin45 = 4.5714285715x² square units. Shaded Ratio is; 4.5714285715x²÷16x² = 0.2857142857

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2262781

Let the inscribed purple regular heptagon side be 1 unit. a = ⅐(180*5) a = ⅐(900)° b = 180-⅐(900)) b = ⅐(360)° c = 180-2(⅐(360)) c = ⅐(540)° (1/sin⅐(540)) = (d/sin⅐(360)) d = 0.8019377358 unit. e = 2(0.8019377358)+1 e = 2.60387547161 units. f = 90-½(⅐(540)) f = ⅐(360)° cos⅐(360) = g/2.60387547161 g = 1.62348980186 units. h = 2g h = 3.24697960372 units. Where h is the base of the ascribed quadrilateral. cos(180/7) = i/0.8019377358 i = 0.72252093395 unit. j = 2i j = 1.4450418679 units...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2261681

Calculating x. (6+12)² = (6+x)²+(12+x)² 18² = 36+12x+x²+144+24x+x² 324 = 180+36x+2x² 2x²+36x+180-324 = 0 2x²+36x-144 = 0 x²+18x-72 = 0 Resolving the quadratic equation. (x+9)² = 72+81 x+9 = ±√(153) x = -9±√(153) It implies; x ≠ -9-√(153) x = (-9+√(153)) units. x = 3.3693168769 units. Calculating area green. a = 6+x a = 6+(-9+√(153)) a = (-3+√(153)) units. b = 12+x b = 12+(-9+√(153)) b = (3+√(153)) units. Green Area (area right-angled triangle) is; ½(ab) =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2261651

Let the square side be a. b² = 3²+4² b = √(25) b = 5 units. tanc = 3/4 c = atan(¾)° d = 90-c d = 90-atan(¾) d = atan(4/3)° It implies; Calculating a, the square side. tan(d) = a/(5-a) tan(atan(4/3)) = a/(5-a) (4/3) = a/(5-a) 3a = 20-4a 7a = 20 a = (20/7) units. Therefore; a² (square area) is; (20/7)² = (400/49) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2260176

Let a be the diameter of the semi circle. a² = b²+14² b² = a²-196 b = √(a²-196) It implies; b² = 6²+6²-2*6*6(-cosc) a²-196 = 72+72cosc a²-196-72 = 72cosc 72cosc = a²-268 cosc = (a²-268)/72 --- (1). cosc = 14/a --- (2). Equating (1) and (2). cosc = cosc (a²-268)/72 = 14/a a³-268a = 1008 a³-268a-1008 = 0 Resolving the polynomial equation. a = 18 units. It implies; Radius, r of the semi circle is; ½(a) = ½(18) = 9 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2260119

Let BD = 1 unit. It implies; CD = 2BD = 2 units. a = 180-60 a = 120° a is angle ADB. b = 180-120-45 b = 15° b is angle BAD (1/sin15) = (c/sin120) c = 3.346065215 units. c is AB. d² = 3.346065215²+3²-2*3.346065215*3cos45 d = 2.4494897428 units. d is AC. (2.4494897428/sin45) = (3/sine) e = 60° e is angle BAC. f = e-b f = 60-15 f = 45° f is angle CAD. Therefore, the required angle, angle ACB is; Let it be g. g = 180-f-60 g = 180-45-60 g = 180-105 g = 75°

You Searched for "post"

2242 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "post"

2242 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?