a = 180-12-2-46-8
a = 180-68
a = 112°
a is angle ABC.
Let AC be 1 unit.
It implies;
(1/sin112) = (b/sin14)
b = 0.257447904 units.
b is AB.
c = 180-8-2
c = 170°
c is angle ADC.
It implies;
(1/sin170) = (d/sin2)
d = 0.2009781915 units.
d is AD.
e² = 0.2009781915²+0.257447904²-2*0.2009781915*0.257447904cos46
e = 0.1865112432 units.
e is BD.
(0.1865112432/sin46) = (0.2009781915/sinf)
f = 50.8173805282°
f is angle ABD.
It implies;
x (angle CBD) = a-f
x = 112-50.8173805282
x = 61.1826194718°
x = 61.2° to 1 decimal place.
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