a² = 6²+8²
a = √(100)
a = 10 cm.
a is the hypotenuse of the ascribed right-angled triangle.
Let b be the hypotenuse of the blue inscribed right -angled triangle.
It implies, observing similar triangles ratio.
6 = 3
10 = b, cross multiply.
6b = 3*10
b = 5 cm.
Let c be the base of the inscribed blue right-angled triangle.
Calculating c.
5² = 3²+c²
c = √(25-9)
c = √(16)
c = 4 cm.
Therefore, Area Blue is;
½*3*c
= ½*3*4
= 6 cm²
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