Mathematics Question and Solution
a = 10+94
a = 104°
a is angle BAC.
b = 24+34
b = 58°
b is angle ABC.
Let AB = 1 unit.
c = 180-58-104
c = 180-162
c = 18°
c is angle ACB.
It implies;
(1/sin18) = (d/sin104)
d = 3.1399429285 units.
d is BC.
e = 180-94-24
e = 108-118
e = 62°
e is angle ADC.
It implies;
(1/sin62) = (f/sin94)
f = 1.129811167 units.
f is BD
g² = 1.129811167²+3.1399429285²-2*1.129811167*3.1399429285cos34
g = 2.2920782452 units.
g is CD.
Calculating x, angle BCD.
(2.2920782452/sin34) = (1.129811167/sinx)
sinx = 0.2756373558
x = asin(0.2756373558)
x = 16.0000000007°
x = 16°
