By OnlineEdumath   |  6th June, 2024
Calculating R. a²+3² = R² a = √(R²-9) units. b = 1+a b = (1+√(R²-9)) units. c = a-1 c = (√(R²-9)-1) units. d²+1² = R² d = √(R²-1) units. e = 3+d e = (3+√(R²-1)) units. f = d-...
By OnlineEdumath   |  6th June, 2024
Let r be the radius of the circle. a = (r-1) units. b = (r-0.5) units. Calculating r. It implies; r² = (r-1)²+(r-0.5)² r² = r²-2r+1+r²-r+(¼) 0 = r²-3r+(5/4) 4r²-12r+5 = 0 4r²-2r-...
By OnlineEdumath   |  5th June, 2024
Let a be 1 units. a is the side length of the regular hexagon. Calculating b. c = 120-90 c = 30° 120° is the single interior angle of the regular hexagon. cos30 = 1/d d = 2/√(3) d = ⅓(2√(3)) unit...
By OnlineEdumath   |  5th June, 2024
a = 6+4 a = 10 cm. b²+6² = 10² b = √(100-36) b = √(64) b = 8 cm. c = b+4 c = 12 cm. d = c-r d = (12-r) cm. r is the ascribed half circle radius. e = 6+d e = 6+(12-r) e = (18-r)...
By OnlineEdumath   |  5th June, 2024
Let the three equal lengths be 1 unit each. a² = 1²+1² a = √(2) units. b = 150-45 b = 105° c² = √(2)²+1²+2√(2)cos 105 c = 1.9318516526 units. (1.9318516526/sin105) = (1/sind) d = 30...
By OnlineEdumath   |  5th June, 2024
Let AD be 4 units. Therefore; AB will be; ½(AD)+½(½(AD)) AB = ½(4)+½(½(4)) AB = 2+1 AB = 3 units. Area ABCD is; 4*3 = 12 square units. Calculating Area Red (Area Trapezoid)....
By OnlineEdumath   |  5th June, 2024
9² = 16²+17²-2*16*17cosa 81 = 545-544cosa 544cosa = 545-81 cosa = 464/544 a = 31.4669762933° 13² = 16²+11²-2*16*11cosb 169 = 377-352cosb 352cosb = 377-169 cosb = (208/352) b = 53.7784533...
By OnlineEdumath   |  5th June, 2024
Let the side length of the red square be a units. b²+3² = a² b = √(a²-9) units. c²+6² = a² c = √(a²-36) units. Observing similar plane shape (right-angled) side length ratios. √(a²-9)...
By OnlineEdumath   |  4th June, 2024
Notice; Diameter of the inscribed semi circle is ½ unit. Therefore radius of the inscribed semi circle is ¼ unit. Let the radius of the inscribed small circle be r. Calculating r. (1...
By OnlineEdumath   |  4th June, 2024
Radius of the inscribed quarter circle is 36 cm. Radius of the inscribed semi circle is; ½(½(36))=9 cm. Radius of the small inscribed circle is; ⅓(⅓(36))=4 cm. Therefore the side lengths...
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