Radius of the quarter circle is (2+3) = 5 units.
Let a be the side length of the inscribed square.
b²+3² = a²
b = √(a²-9) units.
c = 3+b
c = (3+√(a²-9)) units.
Calculating a.
(3+√(...
Sir Mike Ambrose is the author of the question.
Let the ascribed quarter circle radius be 4 units.
Therefore;
Area blue is;
Area triangle with two side 1 unit and 3 units, and angle 2asin(...
Let a be the radius of the circle.
10² = 2a²+2a²cosd
50 = a²+a²cosd --- (1).
10² = (2a)²+e²
e = √(100-4a²) units.
√(100-4a²)² = 2a²-2a²cosd
100-2a² = 2a²-2a²cosd
2a²cosd = 4a²-100
cos...
Sir Mike Ambrose is the author of the question.
Let the side of the regular pentagon be 2 units.
cos36 = a/2
a = 1.61803398875 units.
Where a is the radius of the semi circle.
Area semi-ci...
Let a be the radius of the semi circle.
b²+24² = (2a)²
b = √(4a²-576) units.
b is BC.
c = b-BP
c = (√(4a²-576)-7) units.
c is CP.
It implies;
Calculating a.
2a - (√(4a²-576)-7)...
Calculating the required angle, theta.
Let it be a.
Let the side length of the 4 congruent squares be 1 unit each.
Therefore.
tanb = 1/3
b = atan(⅓)°
tanc = 1/(½)
c = atan(2)°
d...
Calculating Silver Area.
a² = 6²+(0.5*16)²
a = √(100)
a = 10 cm.
a is the radius of the inscribed sector.
tanb = 8/6
b = atan(4/3)°
c = 2b
c = 2atan(4/3)°
c is the angle of the inscr...
Sir Mike Ambrose is the author of the question.
Area green total exactly in decimal cm² is;
Area triangle with two side (12-6√(3)) cm each and angle 60° + Area triangle with side 3.46410161514...
a² = 1²+4²
a = √(17) units.
a is the diameter of the circle.
r, radius of the circle is;
½(a)
r = ½√(17) units.
Notice!
AB = BC
Let AB = BC be a.
b²+(0.5(8+10))² = a²
b = √(a²-81) units.
c = ½(10+8)-8
c = 1 unit.
√(a²-81) - 1
9 - √(a²-81)
Cross Multiply.
a²-81 = 9
a² = 90
a = √(90)...
