Let the side length of the regular heptagon be 1 unit.
Calculating angle x.
a = ⅐*180(7-2)
a = ⅐(900)°
a is the single interior angle of the regular heptagon.
b = ½(360-2*⅐(900))
b = 180-⅐(900)
b = ⅐(360)°
c = ⅐(900)-90
c = ⅐(270)°
sin(⅐(270)) = d/1
d = 0.62348980186 units.
e = 1+2d
e = 2.24697960372 units.
f = ⅐(360)-⅐(270)
f = ⅐(90)°
Therefore, the required angle, x is;
x = 180-g
Calculating g.
(2.24697960372/sing) = (1/sin(⅐(90)))
g = 30°
It implies;
x = 180-30
x = 150°
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