Mathematics Question and Solution
Let AB be 1 unit.
a = 180-24-45
a = 111°
a is angle AED.
(1/sin111) = (b/sin24)
b = 0.43567391896 units.
b is ED.
c = √(2) units.
c is BD.
d = √(2)-0.43567391896
d = 0.97853964341 units.
d is BE.
(CE)² = 0.97853964341²+1-2*0.97853964341cos45
CE = 0.75741388863 units.
(0.75741388863/sin45) = (0.97853964341/sine)
e = 66°
e is angle ECB.
f = 90-66
f = 24°
f is angle DCE.
g = 90+24
g = 114°
g is angle ECF.
Therefore, the required angle x is;
180-114-24
= 42°
