Area red/Area Blue = ⅓
Please, move the above question left/right one time to review the solution of the question.
Thank you kindly.
3^(x) - √(3)^(x)*√(3)^(6) = -162
3^(x) - 3^(x/2)*3^(3) = -162
Let p be 3^(x)
p - 27p^(½) + 162 = 0
p-18p^(½)-9p^(½)p+162 = 0
p^(½)(p^(½)-18)-9(p^(½)-18) = 0
(p^(½)-18) = 0 or (p^(...
Let 1 unit be AB = AC.
a = 12+24
a = 36°
a is angle ABC = angle ACB.
b = 180-2(a)
b = 180-72
b = 108°
b is angle BAC.
c = b-6
c = 108-6
c = 102°
c is angle CAD.
d = 180-12-6
d...
Notice;
Hexagon Area = 24√(3) square units.
Calculating hexagon side length.
Let it be a.
(6a²)/(4tan30) = 24√(3)
½(3√(3))a² = 24√(3)
3a² = 48
a = 4 units.
Equation of the curve i...
Let the radius of the inscribed half circle be 1 unit.
Area rectangle is;
2*1
= 2 square units.
Calculating Shaded Area as a single fraction..
It is;
½(1*2) - 1² + ¼(1)²π - ((180-2a...
Sir Mike Ambrose is the author of the question.
The side of area green, inscribed square is;
Let it be x.
Therefore;
1.11496246101x + 0.82101781219x = 27.3672604063
1.9359802732x = 27....
a² = 10²+16²-2*10*16cos120
a = 2√(129) units.
Where a is length AC.
(3√(129)/sin120) = (16/sinb)
b = 37.58908946897°
c = 90-b
c = 52.41091053103°
d = 60-b
d = 22.41091053103°
e...
Sir Mike Ambrose is the author of the question.
Let the two equal marked lengths of triangle ABC be 2 units.
Therefore;
Area triangle ABC is;
Area triangle with height 5.75877048314 uni...
Sir Mike Ambrose is the author of the question.
Let AC be 1 unit.
Area smaller pentagon is;
½(5)*(1/(2tan(36)))
= 1.72047740059 square units.
a² = 1²+0.5²-cos108
a = 1.24860602048 uni...
Sir Mike Ambrose is the author of the question.
Area yellow is;
Area triangle with two side 8√(2) cm and 2 cm, and angle 45° - Area triangle with height (20/3) cm and base ⅓(20tan(45-2atan(⅓)...
