Mathematics Question and Solution
Let 1 unit be AB = AC.
a = 12+24
a = 36°
a is angle ABC = angle ACB.
b = 180-2(a)
b = 180-72
b = 108°
b is angle BAC.
c = b-6
c = 108-6
c = 102°
c is angle CAD.
d = 180-12-6
d = 162°
d is angle ADB.
It implies;
(1/sin162) = (e/sin12)
e = 0.6728163648 units.
e is AD.
f² = 0.6728163648²+1²-2*0.6728163648*1cos102
f = 1.3162274259 units.
f is CD.
Therefore, the required angle, x is;
(1.3162274259/sin102) = (0.6728163648/sinx)
x = 30°
x is angle ACD.
