Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
6th June, 2025

Calculating Total Shaded Area, Area Grey, Purple and Blue.


Notice.

KLMN is a square.


Calculating area grey.


a = 6-4

a = 2 units.


sinb = 2/6

b = asin(⅓)

b = 19.4712206345°


c²+2² = 6²

c = 4√(2) units.


Area Grey is;


(6*2)-½(4√(2)*2)-(19.4712206345π*6²/360)


= 0.22608138033 square units.


Calculating area purple.


d = (90-b)

d = 70.5287793655°


e = ½(d)

e = 35.2643896828°


f = e+b

f = 35.2643896828+19.4712206345

f = 54.7356103173°


g = ½(180-f)

g = 62.6321948414°


h = 90-g

h = 27.3678051587°


(4/sin27.3678051587) = (2/sinj)

j = 13.28826561°


k = j+h

k = 40.6560707687°


Area purple is;


(6*6)-(40.6560707687π*4²÷360)-(35.2643896828π*6²÷360)-(0.5*6²sin54.7356103173)-(0.5*2*4sin40.6560707687)


= 36-5.6766583667-11.0786347561-14.6969384567-2.60606777301


= 1.94170064749 square units.


Calculating area blue.


l = 4√(2)-2

l = 3.65685424949 units.


m² = 6²+6²-2*6*6cos35.2643896828

m = 3.63486535834 units.


n = 90-k

n = 90-40.6560707687

n = 49.3439292313°


o² = 4²+4²-2*4*4cos49.3439292313

o = 3.33937985499 units.


3.33937985499² = 3.63486535834²+3.65685424949²-2*3.65685424949*3.63486535834cosp


26.5843456639cosp = 15.4333713594


p = acos(15.4333713594/26.5843456639)

p = 54.5112153403°


Area blue is;


(0.5*3.63486535834*3.65685424949

cos54.5112153403)+(49.3439292313π*4*4÷360)-(0.5*4*4sin49.3439292313)+(35.2643896828π*6*6÷360)-(0.5*6*6sin35.2643896828)


= 5.41143744109+6.88971224766-6.06907266803+11.0786347561-10.3923048454


= 6.91840693142 square units.


Therefore, total shaded area is;


0.22608138033+1.94170064749+6.91840693142


= 9.08618895924 square units.


≈ 9.1 square units to 1 decimal place.

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