Let the square side be 2 units.
Area Square is;
2²
= 4 square units.
tana = ½
a = atan(½)°
b = 2a
b = 2atan(½)°
c = (180-2atan(½))°
d = atan(2)°
e = (180-2atan(½))-atan(2)
e = (90-atan(½))°
t...
Sir Mike Ambrose is the author of the question.
a = atan(2)°
b = (45+atan(½))°
(a) Calculating Alpha.
Let alpha be c.
c = 180-b
c = 180-45-atan(½)
c = (135-atan(½))°
Or
c = 180-(135-atan2)
c = (...
Let the side length of the regular hexagon be 1 unit.
Calculating the side length of the regular pentagon.
Let it be b.
(2/sin72) = (a/sin60)
a = 1.82118599462 units.
(1.82118599462/sin108) = (b/...
Sir Mike Ambrose is the author of the question.
a² = 8²+12²-2*8*12cos60
a = 4√(7) cm.
b = 2a
b = 8√(7) cm.
(4√(7)/sin60) = (8/sinc)
c = 40.89339464928°
(16/sin40.89339464928) = (8√(7)/Sind)
d = 6...
20² = 12²+a²
a² = 400-144
a = √(256)
a = 16 cm.
b = 16-9
b = 7 cm.
c = atan(3/4)°
Let Alpha be d.
d = ½(c)
d = 0.5atan(¾)°
tan(0.5atan(¾)) = e/16
e = ⅓(16) cm.
tan(0.5atan(¾))...
Sir Mike Ambrose is the author of the question.
a² = 32-32cos120
a = 4√(3) units.
b = 2a
b = 8√(3) units.
c² =32-32cos150
c = 7.72740661031 units.
sin30 = d/4
d = 2 units.
sin60 = e/...
Calculating x.
½(x+2)(x-2) = 30
x²-4 = 60
x² = 64
x = 8 m.
Therefore;
AB = 8-2 = 6 m.
BC = 8+2 = 10 m.
It implies;
L² = 6²+10²
L² = 36+100
L² = 136
L = √(136)
L = √(2*2*34)
L = 2√(34) m.
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Sir Mike Ambrose is the author of the question.
a = atan(¼)°
b² = 12²+3²
b = 3√(17) cm.
c = ½(atan (4/3))°
Let the radius of the inscribed circle be r.
Calculating r.
tan(½(atan(4/3))) = (r/(9-r)...
Let the side length of the regular pentagon be a.
b² = a²+(0.5a)²-2*a*(0.5a)cos108
b = 1.24860602048a units.
Calculating angle AGE.
Let it be c.
(1.24860602048a/sin108) = (a/sinc)
c = 49.6138224...
