Let the base of the ascribed triangle be 1 unit.
a = 180-70-70
a = 40°
(b/sin40) = (1/sin70)
b = 0.6840402867 units.
Considering similar plane shape (isosceles triangle) side length ratios.
1 - 0.6840402867
(0.6840402867+c) - 1
Cross Multiply.
1 = 0.6840402867²+0.6840402867c
(1-0.6840402867²) = 0.6840402867c
c = 0.7778619133 units.
d = 70-40
d = 30°
e² = 1²+0.7778619133²-2*0.7778619133cos30
e = 0.507713306 units.
Therefore, the required angle, x is;
(0.507713306/sin30) = (0.7778619133/sinx)
x = 50°
Again, x is the required angle.
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