since tanx = 3/4, it implies;
Let AB = 4 units.
Let AD = 3 units.
tana = 4/3
a = atan(4/3)°
a is angle ADB.
b = 180-a
b = 90+90-atan(4/3)
b = (90+atan(3/4))°
b is angle BDC.
It...
Sir Mike Ambrose is the author of the question.
Area Gold exactly in square cm decimal form is;
Area trapezium with two parallel side 6√(13) cm and 14.9769052981 cm, and height 11.6487041207 cm...
Let the two equal inscribed right-angled triangle side lengths be a each.
Calculating a.
0.5a² = 50
a² = 100
a = 10 units.
a is EU.
Notice!
Arc TU = Arc US.
Let b be the radius of...
Blue area is;
½(2.5)²π - (180-2atan(3/4))π(2²)/360 + 0.5*2²sin(180-2atan(3/4)) - (180-2atan(4/3))π(1.5)²/360 + 0.5*1.5²sin(180-2atan(4/3)) + ½(4*3) - 2atan(4/3)π(1.5²)/360 + 0.5(1.5²)sin(2atan(4...
Let the side of the regular pentagon be 1 unit.
Calculating Area Red.
a² = 1²+1²-2*1*1cos108
a = 1.61803398875 units.
b = 108-36-60
b = 12°
(c/sin12) = (1.61803398875/sin96)
c = 0.33...
Sir Mike Ambrose is the author of the question.
Let the side of the square be 2 units.
Therefore;
Area square is;
2²
= 4 square units.
Area S is;
Area triangle with two side 0.9892...
Let the square side be 2 units.
tan30 = a/2
a = ⅓(2√(3)) unit.
sin60 = 2/b
b = ⅓(4√(3)) units.
c = 2-a
c = ⅓(6-2√(3)) units.
It implies;
Area Shaded is;
2(½*(⅓(6-2√(3)))²sin60)...
Sir Mike Ambrose is the author of the question.
Shaded area coordinates are;
Coordinate X is;
X(½, (9/4))
Coordinate Y is;
Y((-3/2), (17/4))
Coordinate Z is;
Z((5/2), (33/4))...
Let the side of the regular octagon be a.
Calculating a.
a² = 8
a = √(8)
a = 2√(2) units.
2b² = (2√(2))²
b = 2 units.
c = 2√(2)+2+2
c = (2√(2)+4) units.
Where c is the length of...
Sir Mike Ambrose is the author of the question.
Let the radius of the semi circle be 1 unit.
cos20 = a/2
a = 1.87938524157 units.
cos20 = 1/b
b = 1.06417777248 units.
c = a-b
c = 0.815...
