Sir Mike Ambrose is the author of the question.
Let the single side length of the equilateral triangle be 2 unit.
Therefore;
Area Green is;
⅓√(3) * ⅔
= 2√(3)/9 square units.
Area Yellow...
Let the single side length of the blue area/square be x.
Therefore;
5² = x² + (x+½(5-x))²
5² = x² + (½(5+x))²
25 = x² + ¼(25+10x+x²)
100 = 4x²+25+10x+x²
5x²+10x-75=0
x²+2x-15=0
(x+1)²=1...
a = 15+5
a = 20 units.
a is the radius of the circle.
d² = b²+c² --- (1).
Where b is the width of the inscribed blue rectangle area and c is the length.
15²+20² = d²
d = 25 units.
d is t...
Area red is;
Area semi circle with radius 5 cm - Area sector with radius 5 cm and angle (180-2atan(2))° - Area kite with diagonal lengths √(10²+5²) cm and √(200-200cos(2atan(½))) cm + Area secto...
Area red is;
Area square with length 5 cm - Area quarter circle with radius 5 cm - Area sector with radius 2.5 cm and angle (180-2atan(2))° - Area kite with diagonal lengths √(5²+(2.5)²) cm and...
Calculating z, the diagonal of the square.
9 - 14
y - 7
Cross Multiply.
Therefore;
14y = 63-9y
23y = 63
y = 63/23 units.
z = √(9²+y²)+√(14²+(7-y)²)
And y = 63/23 units.
z...
a² = 4
a = 2 cm.
a is the side length of the inscribed square.
b² = 2a²
b = √(2*2*2)
b = 2√(2) cm.
b is the radius of the ascribed semi circle.
tanc = 2/(2√(2))
c = atan(1/√(2))°
The...
Since;
AB = 2BC
It implies;
AB = (2/3)*12
AB = 8 cm.
BC = (1/3)*12
BC = 4 cm.
12 cm is the side length of the ascribed square.
tana = 12/8
a = atan(3/2)°
b = 90-a
b = atan(2/...
Sir Mike Ambrose is the author of the question.
Area blue is;
Area triangle with side 8.81712800181 cm and 7.80776406404 cm, and angle 19.3341412463°
= ½(8.81712800181*7.80776406404)sin19.3341...
Sir Mike Ambrose is the author of the question.
Area purple exactly in square cm decimal form is;
Area triangle with side 17.1220111351 cm and 15.6524758425 cm, and angle 75.963756532° - Area t...
