By OnlineEdumath   |  26th December, 2024
Sir Mike Ambrose is the author of the question. Length AD is; AD = 3√(15) cm. Therefore; Area Orange exactly in cm² is; Area triangle with height √(15) cm and base 3√(15) cm + Area tri...
By OnlineEdumath   |  26th December, 2024
Let the side length of the regular pentagon be 1 unit. tan36 = a/0.5 a = 0.363271264 units. b² = 0.363271264²+0.5² b = 0.61803398875 units. tan72 = c/0.5 c = 1.53884176859 units. Are...
By OnlineEdumath   |  25th December, 2024
Gradient of the curve at x = 3 is; dy/dx = (-19/20) It implies; Area yellow exactly in square units decimal is; Area triangle with height (5/(4sin(atan(19/20)))) units and base (5/(4sin...
By OnlineEdumath   |  25th December, 2024
a = atan(½)° b² = 2(10)² b = 10√(2) units. c = (45-atan(½))° cos(atan(½)) = d/20 d = 17.88854382 units. Area x is; 0.5*17.88854382*10√(2)sin(45-atan(0.5)) = 40 square units.
By OnlineEdumath   |  25th December, 2024
18² = 14²+16²-2*14*16cosa 448cosa = 14²+16²-18² a = acos((14²+16²-18²)/448) a = 73.39845040098° (18/sin73.39845040098) = (14/sinb) b = 48.18968510422° c = 180-48.18968510422-73.3984504009...
By OnlineEdumath   |  24th December, 2024
Let a be the diameter of the semi circle. a² = b²+14² b² = a²-196 b = √(a²-196) It implies; b² = 6²+6²-2*6*6(-cosc) a²-196 = 72+72cosc a²-196-72 = 72cosc 72cosc = a²-268 cosc = (a²-268...
By OnlineEdumath   |  23rd December, 2024
Let x the the side length of the inscribed green equilateral triangle. Calculating area green. a = 180-60 a = 120° b = 45-30 b = 15° c = 180-120-15 c = 180-135 c = 45° d = (4+√(6...
By OnlineEdumath   |  23rd December, 2024
Sir Mike Ambrose is the author of the question. Let alpha be x. Therefore; (12/sin2x)=(8/sinx) And; Sin2x = 2sinxcosx Therefore; (12/2sinxcos)=(8/sinx) 6 = 8cosx x = acos(6/8)°...
By OnlineEdumath   |  22nd December, 2024
Sir Mike Ambrose is the author of the question. Let the side length of the green regular hexagon be 1 unit. Therefore the angle theta to 2 d. p. is; (atan(0.5÷(tan72-sin60)) + atan(0.5÷(tan7...
By OnlineEdumath   |  22nd December, 2024
Sir Mike Ambrose is the author of the question. Area green exactly in cm² is; Area ABCD - Area trapezoid with parallel sides (9-2√(3)) cm and (24√(3)-39) cm, and height 6 cm. = (54-6√(3)) - ½...
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