Sir Mike Ambrose is the author of the question.
Let the single side length of the square be 2 unit.
Therefore;
Area square is;
2²
= 4 square units
It implies;
Area R is;
Area sector with radius 2 unit and angle 8.130127545°
- Area triangle with height 1.61624318301 unit and base (1.37930921037sin8.130127545) unit
= (8.130127545*4π÷360) - (½*1.61624318301*1.37930921037sin8.130127545)
= 0.28379498853 - 0.15763573684
= 0.12615925169 square unit
Therefore;
Area Square ÷ Area R to 1 d. p. is
4 ÷ 0.12615925169
= 31.7059585121
≈ 31.7
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