Let the radius, r of the circle be 7 units.
Therefore perimeter of the circle is;
2πr
= 44 units.
Calculating the length of the square.
14² = (14-2x)²+(14-4x)²
196 = 196-56x+4x²+196-112x+16x²
20x²-168x+196=0
5x²-42x+49=0
(x-(21/5))²= (-49/5)+(-21/5)²
(x-(21/5))²= (196/25)
x = (21/5)±(14/5)
x = (21±14)/5
x ≠ (35/5) ≠ 7
x = (7/5) units.
It implies;
The square length is;
14-2x, and x = (7/5) units.
= 14-2(7/5)
= (70-14)/5
= 56/5 units.
Therefore perimeter of the square is;
4(56/5)
= 224/5 units.
= 44.8 units.
The implication of the above derivatives is that the perimeter of the square is larger.😀😄
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