tan60 = a/5
a = 5√(3) cm.
Where a is AD.
b = ½(a)
b = ½(5√(3)) cm
c = atan((½(5√(3))/5)
c = atan(½√(3))
Where c is angle AGB
d = atan(5√(3)/5)
d = atan(√(3))
Where d is angle CAG.
e = 180-c-d
e...
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Educators;
Mr. Ovo, Mr. Da...
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We make teaching and learning Mathematics fun for learners, we expose the simplicit...
tanx = 4/(40-4)
tanx = (1/9)
x = atan(1/9)
y = 2x
y = 2atan(1/9)
Therefore;
tan(2atan(1/9)) = h/40
(9/40) = (h/40)
h = 9 units.
Let AB = x
Let r be the radius of the semi circle.
It implies;
OC = x-r
y = √(r²-(x-r)²)
y = √(r²-(x²-2xr+r²))
y = √(2xr-x²)
Therefore;
6²+r² = (x-r)²+(2+√(2xr-x²))²
6²+r² = x²-2xr+r²+4+4√(2xr...
r² = x²+√(8)²
x = √(r²-8) units.
Calculating r, radius of the semi circle.
3² = x²+(√(8)-(r/2))²
9 = √(r²-8)²+8-2√(2)r+(r²/4)
9 = r²-8+8-2√(2)r+(r²/4)
36 = 4r²-8√(2)r+r²
5r²-8√(2)r-36 = 0
Solvin...
Please, move a step right to review the analyzed figure.
Considering similar triangle ABG ratios.
AG = x
12 = 12-x
It implies;
AG = 12x/(12-x)
Notice;
Angle ABG = Angle EFI, therefore consider...
Let the forward diagonal of the quadrilateral be 2 units.
(2/sin110) = (a/sin35)
a = 1.22077458876 units.
(b/sin30) = (2/sin55)
b = 1.22077458876 units.
It implies;
x = ½(180-130)
x = 25°
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Let the base of the ascribed triangle be 1 unit.
a = 180-3-6
a = 171°
(1/sin171) = (b/sin3)
b = 0.33455515209 units.
c = 180-30-87
c = 63°
(1/sin63) = (d/sin30)
d = 0.56116311882 units.
e² = 0....
