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Let the radius of the inscribed circle be r.
The square side is 8 cm.
b = 8-r
c = 2+r
Therefore;
(2+r)² = 2²+(8-r)²
4+4r+r² = 4+64-16r+r²
4r = 64-16r
20r = 64
5r = 16
r = (16/5) cm.
Area circl...
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The triangle's height is;
3x^(⅓)
Triangle area = Triangle perimeter
Therefore;
½(3x^(⅓)*4x^(⅓)) = 12x^(⅓)
6x^(⅔) = 12x^(⅓)
x^(⅔) = 2x^(⅓)
x^(⅓) = 2
Therefore;
x = 8 units....
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Let AB = x
PB = x/4
Therefore;
a = x - (x/4)
a = (3x/4) units.
b² = x²+(3x/4)²
b = √(x²+(3x/4)²) units.
c = (x-4) units.
It implies that;
½(x*(3x/4)) + ½(4*√(x²+(3x/4)²)) + ½(4*(x-4)) + (4*4)...
a = 15-11.25
a = 3.75 m.
b = atan(3/3.75)°
c = 90-atan(3/3.75)
c = 51.34019174591°
Calculating Length CD.
tan(51.34019174591) = 15/CD
CD = 15/tan(51.34019174591)
CD = 12 m.
Red Area is;
7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively.
= 7(1*1) -...
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Prince (year 4), Oghenezino (year 4) and Ogheneruemu (year 4).
Educator: Mr. Dan...
a = 0.5(90-60)
a = 15°
cos15 =4/b
b = 4.14110472164 cm.
Where b is the side length of the inscribed regular triangle purple area.
Purple area is;
Area triangle with height 4.14110472164 cm and b...
