3A = ¼(9*9)π
Where;
3A is the sum of the inscribed three equal areas.
¼(9*9)π is the area of the ascribed quarter circle.
It implies;
12A = 9*9π
A = (27/4)π cm²
A is an area of the three equal are...
Let r be the radius of the inscribed green semi circle.
Notice.
The ascribed triangle is equilateral.
Therefore;
sin60 = r/(0.5*7)
r = 0.5*7sin60
r = 3.0310889132 units.
Again, r is the radius of...
Notice.
Rectangle width is 4 units.
a = 4-1
a = 3 units.
tanb = ½
b = atan(⅓)°
c = 2b
c = 2atan(⅓)°
d = 90-c
d = (90-2atan(⅓))°
tan(½d) = 2/e
tan(0.5(90-2atan(⅓))) = 2/e
e = 2/tan(0.5(90-2atan(⅓...
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(2√(2)/sin135) = (√(2)/sina)
a = 20.70481105464°
b = 180-20.70481105464-135
b = 24.29518894536°
(c/sin24.29518894536) = (2√(2)/sin135)
c = 1.64575131106 units.
Where c is the height of the yellow...
Red Area is;
7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively.
= 7(1*1) -...
Let the radius of the inscribed yellow half circle be x.
Calculating x.
a = tan(3/4)°
a is angle ABC.
b = tan(4/3)°
b is angle BAC.
sin(atan(3/4)) = x/c
c = (5x/3)
c is OB.
sin(a...
Let the inscribed blue square side length be x.
It implies;
Considering side lengths of similar right-angled triangle.
2 - x
x - 6
Therefore;
(2/x) = (x/6)
Cross Multiply.
x² = 12
Area Blue = 1...
Let the side of the green square be x.
Therefore;
x/(tan(atan¾)) + x + x/(tan(atan(4/3))) = 5
⅓(4x) + x + ¼(3x) = 5
16x + 12x + 9x = 60
37x = 60
x = (60/37) units
It implies;
Area squ...
