Let the congruent two inscribed semi circles radius be r.
a = (3-2r) units.
b = 2r units.
It implies, calculating r.
2²+a² = b²
2²+(3-2r)² = (2r)²
4+9-12r+4r² = 4r²
12r = 13
r = (13/12) units.
Again, r is the radius of the inscribed two congruent semi circles.
Are Blue is;
Area rectangle with length 3 units and width 2 units - Area circle with radius (13/12) units.
= (3*2)-π(13/12)²
= 6-(169/144)π
= (864-169π)/144 square units.
= 2.3129919552 square units.
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