Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
14th April, 2024

a = 36+18

a = 54°


Let one of the green triangle area side be b.


cos54 = c/b

c = bcos54 units.

c = 0.5877852523b units.


sin54 = d/b

d = bsin54 units.

d = 0.8090169944b units.


e = c+d

e = 0.5877852523b+0.8090169944b

e = 1.3968022467b units.


Calculating b.


0.5*1.3968022467b*bsin54 = 22

1.3968022467b² = 44

b² = 31.500522071

b = 5.6125325897 units.


e = 1.3968022467b units.

And b = 5.6125325897 units.

e = 1.3968022467*5.6125325897

e = 7.839598131 units.


f² = 7.839598131²+5.6125325897²-2*7.839598131*5.6125325897cos54

f = 6.4214265334 units.

f is the side length of the bigger regular pentagon.


sin54 = (0.5*5.6125325897)/g

g = 3.4687359034 units.

g is the side length of the big regular pentagon.


(7.839598131/sinh) = (6.4214265334/sin54)

h = 81°


j = 360-81-108-72

j = 99°


k² = 6.4214265334²+3.4687359034²-2*6.4214265334*3.4687359034cos99

k = 7.7611701995 units.

k is the side length of the biggest regular pentagon.


(7.7611701995/sin99) = (3.4687359034/sinl)

l = 26.1952933695°


m = 360-(2*108)-26.1952933695

m = 117.8047066305°


n² = 2(7.7611701995²)-2(7.7611701995²)cos108

n = 12.5578371753 units.


It implies, area red is;


Area triangle with height 12.5578371753 units and base 6.4214265334sin117.8047066305

= 0.5*12.5578371753*6.4214265334sin117.8047066305

= 35.6644190027 square units.

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