Mathematics Question and Solution
a² = 5²+12²
a = 13 cm.
a = AC = BD = diameter of the ascribed circle.
b = ½(13)
b = 6.5 cm.
b = OG = OE = radius of the ascribed circle.
c = atan(6/(6.5+2.5))
c = atan(6/9)
c = 33.69006752598°
c = Angle OEF = Angle BCF.
d = 6.5-2.5
d = 4 cm.
tan33.69006752598 = e/4
e = 8/3 cm.
f = atan((8/3)/(5/2))
f = 46.84761026599°
g = atan(2.5/6)
g = 22.61986494804°
h = 90-22.61986494804-46.84761026599
h = 20.53252478597°
h = Angle BOG.
i = ½(180-20.53252478597)
i = 79.73373760702°
i = Angle OGB = Angle OBG.
It implies;
Length BG is;
(BG/sin20.53252478597) = (6.5/sin79.73373760702)
BG = 2.3168969309 cm.
