Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2439228

Let a be the side length of the purple inscribed square. b² = 4 b = 2 cm. b is the side length of the green inscribed square. c² = 1 c = 1 cm. c is the side length of the yellow ascribed square. d = a-c d = (a-1) cm. e = a-b e = (a-2) cm Calculating a, side length of the inscribed purple square. Considering similar plane shapes (right-angled triangle) side length ratios. d - 2 1 - e It implies; (a-1) - 2 1 - (a-2) Cross Multiply. (a-1)(a-2) = 2 a²-3a+2 = 2 a²-3a = 0 a = 3 cm. Ther...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2439064

Calculating angle x. Let AB be 1 unit. a = 9-20 a = 70° a is angle ABH. b = 180-10-70 b = 100° (c/sin70) = (1/sin100) c = 0.9541888941 units. (d/sin10) = (1/sin100) d = 0.1763269807 units. sin20 = e/1 e = 0.3420201433 units e is BH. cos20 =f/1 f = 0.9396926208 units. f is AH. g = e-d g = 0.3420201433-0.1763269807 g = 0.1656931626 units. h = 180-20-30 h = 130° (1/sin130) = (j/sin30) j = 0.6527036447 units. k = f-j k = 0.9396926208-0.6527036447 k = 0.2869889761 units. Therefore, the...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2438789

Let BC be 1 unit. a = ½(180-45) a = ½(135) a = 67.5° a is angle ABC = angle ACB. (1/sin45) = (b/sin67.5) b = 1.3065629649 units. b is AB. c = 180-45-67.5 c = 67.5° c is angle BEC. It implies; BE = 1 unit. d = 67.5-30 d = 37.5° d is angle BCD. e = 180-67.5-37.5 e = 75° e is angle BDC. (1/sin75) = (f/sin37.5) f = 0.630236207 units. f is BD. g = 67.5-45 g = 22.5° g is angle DBE. h² = 1²+0.630236207²-2*1*0.630236207cos22.5 h = 0.4823619098 units. h is DE...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2437851

Let the side length of the regular pentagon be 1 unit. a = ⅕(180(5-2)) a = 108° a is the single interior angle of the regular pentagon. b² = 2-2cos108 b = 1.6180339887 units. c = ½(180-108) c = 36° d = 108-36 d = 72° e = 180-72-30 e= 78° (1.6180339887/sin78) = (f/sin30) f = 0.8270909153 units. g = 180-78 g = 102° Therefore, the required angle alpha is; Let it be h. (1/sin102) = (0.8270909153/sinh) h = 54°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2437741

Notice! Radius of the ascribed semi circle is 6 cm. It implies; Radius, a of the inscribed bigger circle is; a = ½(6) a = 3 cm. Calculating b, radius of the smaller inscribed circle. c = (6-b) cm. c² = b²+e² (6-b)² = b²+e² e² = 36-12b e = √(36-12b) cm. f = (3-b) cm. g = (3+b) cm. Therefore; g² = f²+e² (3+b)² = (3-b)²+36-12b 9+6b+b² = 9-6b+b²+36-12b 12b = 36-12b 24b = 36 b = (36/24) b = (3/2) cm. Again, b is the radius of the smaller inscribed circle. Painted Area is; Area semi circle...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2437685

Calculating area of the inscribed blue square. Let the inscribed blue square side be x. a² = 2x² a = √(2)x units. a is the diagonal of the inscribed blue square. x² = 2b² b² = x²/2 b = ½√(2)x units. It implies; 1² = a²+b² 1 = 2x²+(x²/2) 1 = ½(5x²) 2 = 5x² x² = (2/5) square units. x² = 0.4 square units. Where x² is the area of the inscribed blue square.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2436610

Notice! AQ = 6 cm. a² = 6²+3²-2*6*3cos108 108° is the single interior angle of the regular pentagon. a = 7.4916361229 cm. a is AP. cosb = 6/7.4916361229 b = acos(6/7.4916361229)° b is angle PAQ. Therefore, area triangle PAQ (area blue) is; 0.5*6*7.4916361229sin(acos(6/7.4916361229)) = 13.4581390311 cm² ≈ 13.46 cm² to 2 decimal places.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2436205

(4+5+3)² = 2a² a² = 72 a = 6√(2) cm. a is the congruent adjacent sides of the right-angled triangle. b² = √(72)²+3²-2*√(72)*3cos45 b² = 81-36 b = √(45) b = 3√(5) cm. (3√(5)/sin45) = (3/sinc) c = 18.4349488229° d² = √(72)²+4²-2*√(72)*4cos45 d² = 88-48 d = √(40) d = 2√(10) cm. (2√(10)/sin45) = (4/sine) e = 26.5650511771° f = 90-c-e f = 90-18.4349488229-26.5650511771 f = 45° 2g² = 5² g² = 25/2 g = √(25/2) g = ½(5√(2)) cm. g = 3.5355339059 cm. It implies; Shaded Area is; Area quarter circl...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2435756

Let the base of the ascribed triangle be 1 unit. a = 180-20-20-10-10 a = 120° (1/sin120) = (b/sin20) b = 0.3949308436 units. c = 180-120-20 c = 40° (0.3949308436/sin40) = (d/sin120) d = 0.5320888862 units. e = 180-40-60 e = 80° (0.3949308436/sin80) = (f/sin60) f = 0.3472963553 units. g² = 0.3472963553²+0.5320888862²-2*0.3472963553*0.5320888862cos20 g = 0.2375646984 units. (0.2375646984/sin20) = (0.5320888862/sinh) h = 50° j = 180-h j = 180-50 j = 130° Therefore the required angle x,...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2435595

a = 180-20-50-40 a = 70° It implies the triangle is isosceles. Let the base of the isosceles triangle be 1 unit. 1² = 2b²-2b²cos40 1 = 0.4679111138b² b = √(1/0.4679111138) b = 1.4619022 units. b is the two equal lengths of the isosceles triangle. c = 180-40-20 c = 120° (1.4619022/sin120) = (d/sin20) d = 0.5773502692 units. (1.4619022/sin120) = (e/sin40) e = 1.0850635751 units. f = e-d f = 1.0850635751-0.5773502692 f = 0.5077133059 units. g = b-d g = 1.461902...

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2620 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2620 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?