Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2940069

a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.41091053103° d = 60-b d = 22.41091053103° e = 90-d e = 67.58908946897° f = 90-60 f = 30° cos37.58908946897 = g/10 g = 7.92405815693 units. i = 30+37.58908946897 i = 67.58908946897° tan67.58908946897 = j/7.92405815693 j = 19.2148198619 units. Where j is the radius of the arc. sin67.58908946897 = 19.2148198619/k k = 20....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2932593

a² = 15²+12²-2*12*15cos120 a = 23.43074902772 cm. Where a is the side length of the equilateral triangle ABC. (23.43074902772/sin120) = (12/sinb) b = 26.32950349168° c = 60-b c = 33.67049650832° d² = 15²+15²-2*15*15cos120 d = 25.98076211353 cm. e = atan(7.5/25.98076211353) e = 16.10211375199° f = 90-e f = 73.89788624801° g = 180-f-c g = 72.43161724367° (15/sin72.43161724367) = (h/sin73.89788624801) h = 15.11661227595 cm. i = a-h i = 8.31413675177 cm. L...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2922210

Area of coloured region is; Area triangle with height 53.3479501083 m and base 60sin(102.042575143) m + Area triangle with height 100.027406452 m and base √(5924)sin(12.5245961777) m = (½*53.3479501083*60sin(102.042575143)) + (½*100.027406452*√(5924)sin(12.5245961777)) = 1565.21739131 + 834.782608691 = 2400 m²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2911891

Sir Mike Ambrose is the author of the question. AB exactly is; = 16tan(3acos(8/9)) - 2√(17) = 2(8tan(3acos(8/9))-√(17)) cm. = 102.760478669 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2883975

Let the side of the regular pentagon be 1 unit. a = 108-90 a = 18° b = 180-108-18 b = 54° (1/sin54) = (c/sin108) c = 1.17557050458 units. (1/sin54) = (d/sin18) d = 0.38196601125 units. e = 1-d e = 0.61803398875 units. f² = 0.61803398875²+1²-2*0.61803398875cos108 f = 1.3281310261 units. (1.3281310261/sin108) = (1/sing) g = 45.73230144788° h = 180-108-45.73230144788 h = 26.26769855212° I = 180-72-45.73230144788 i = 62.26769855212° (0.61803398875/sin62.26...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2858517

Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angle 45° = 0.5*1.03528*0.53589838486sin45 = 0.1961531464 space units. Area R is; Area triangle with two side (2√(2)-2) units and 0.65961372961 units, and angle 72.367664609° = 0.5*(2√(2)-2)*0.65961372961sin72.367664609 = 0.26038499708 space units. Area T is; Area sector with...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2857013

Let 1 unit be AB = AC. a = 12+24 a = 36° a is angle ABC = angle ACB. b = 180-2(a) b = 180-72 b = 108° b is angle BAC. c = b-6 c = 108-6 c = 102° c is angle CAD. d = 180-12-6 d = 162° d is angle ADB. It implies; (1/sin162) = (e/sin12) e = 0.6728163648 units. e is AD. f² = 0.6728163648²+1²-2*0.6728163648*1cos102 f = 1.3162274259 units. f is CD. Therefore, the required angle, x is; (1.3162274259/sin102) = (0.6728163648/sinx) x = 30° x is angle ACD.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2855149

a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.41091053103° d = 60-b d = 22.41091053103° e = 90-d e = 67.58908946897° f = 90-60 f = 30° cos37.58908946897 = g/10 g = 7.92405815693 units. i = 30+37.58908946897 i = 67.58908946897° tan67.58908946897 = j/7.92405815693 j = 19.2148198619 units. Where j is the radius of the arc. sin67.58908946897 = 19.2148198619/k k = 20....

Mathematics Question and Solution.

https://onlineedumath.com/update/mathematics-question-and-solution/2840743

Sir Mike Ambrose is the author of the question. Let AB be 2 unit. Therefore CD = 1 unit. It implies; Area Blue is; Area triangle with height 0.72111025509 unit and base sin(atan(3/2)) unit. = 0.5*0.72111025509sin(atan(3/2)) = 3/10 space unit. Area Green is; Area trapezoid with two parallel side (3/2) unit and 1 unit, and height ½ unit - Area triangle with height (3/2) unit and base ½ unit. = ½*½((3/2)+1) - ½*½(3/2) = (5/8) - (3/8) = ¼ space unit. Area Red is; Area...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2834872

Calculating r, radius of the circle. (r/tan40)+(r/tan30) = 10 r = 3.42020143326 cm. (a/sin60) = (10/sin40) a = 13.47296355334 cm. tan40 = 3.42020143326/b b = 4.07603734548 (4.07603734548/sin50) = (c/sin80) c = 5.24005260459 cm. d = 13.47296355334-4.07603734548 d = 9.39692620786 cm. e² = 9.39692620786²+5.24005260459²-2*9.39692620786*5.24005260459cos130 e = 13.38142726359 cm. (13.38142726359/sin130) = (5.24005260459/sinf) f = 17.45618925878° g = 100-17.4561892587...

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