You Searched for "102"

252 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3159871

mathematics-question-and-solution_1752205578bOIMJe.jpeg
Let a = AB = AD = CD. b² = 2a² b = √(2)a units. b is BD. Notice. Triangle BCD is a right-angled triangle, where BC is the hypotenuse. c² =(√(2)a)²+a² c = 3a² c = √(3)a units. c is BC. cosd = (0.5*10)/a cosd = 5/a --- (1). d is angle CAD. From (1). sind = √(a²-25)/a --- (2). (√(3)a)² = a²+10²-2a*10cos(90-d) 3a² = a²+100-20a(cos90cosd+sin90sind) 2a² = 100-20a(sind) a² = 50-10asind --- (3). Calculating a. Substituting (2) in (3). a² = 50-10a√(a²-25)/a a² = 50-10√(a²-25) 10²(a²-25) =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3157724

mathematics-question-and-solution_1752118906GKE6pz.jpeg
Calculating the radius of the inscribed circle. a²+6² = 10² a = √(64) a = 8 units. Let x be the radius of the inscribed half circle. Calculating x. b = (8-x) units. c = (6-x) units. It implies; x ~ (8-x) (6-x) ~ x Cross Multiply. x² = 48-14x+x²  14x = 48 x = ⅐(24) units. Recall. b = (8-x) And x = ⅐(24) units. b = 8-⅐(24) b = ⅐(32) units. tand = ⅐(24)÷⅐(32) d = atan(3/4)° Let y be the radius of the inscribed circle. tan(0.5atan(3/4)) = y/(⅐(32)) ⅓ = 7y/32 21y = 32 y = (32/21) uni...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3150389

mathematics-question-and-solution_1751671283AcT0Ma.jpeg
a = ½(10) a = 5 units. a is the radius of the ascribed half circle. cosb = 4/5 b = 36.8698976458° b is angle alpha. c²+8² = 10² c = √(100-64) c = 6 units. sin(2acos(4/5)) = d/10 d = 9.6 units. cosf = (0.5*9.6)/6 cosf = 4.8/6 f = acos(0.8)° tan(0.5acos(0.8)) = g/(0.5*9.6) g = 4.8tan(0.5acos(0.8)) g = 1.6 units. g is the radius of the inscribed circle. Area inscribed circle is; πg² = π(1.6)² = 2.56π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3145292

mathematics-question-and-solution_1751261636c59HfB.jpeg
Calculating shaded area. tana = 5/10 a = atan(½)° Therefore; b = atan(2)° c = 90-2a c = 90-2atan(½) c = 36.8698976458° d = 180-2b d = 180-2atan(2) d = 53.1301023542° Shaded Area is; Area square with length 10 cm - 2(area triangle with height 10 cm and base 5 cm) - Area sector with radius 10 cm and angle 36.8698976458° - Area sector with radius 5 cm and angle 53.1301023542°. = 10²-2(½*10*5)-(36.8698976458π*10²/360)-(53.1301023542π*5²/360) = 100-50-32.1750554396-...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3144604

mathematics-question-and-solution_1751175197GIV6TX.jpeg
Let AC = BD = DE = a. Calculating a. 14² = a²+(10+a)²-2a(10+a)cosb 96 = 2a²+20a-(20a+2a²)cosb --- (1). 14² = a²+10²+2a*10cosb 96 = a²+20acosb cosb = (96-a²)/(20a) --- (2). Substituting (2) in (1). 96 = 2a²+20a-(20a+2a²)(96-a²)/(20a) Therefore; a = 6 units. Recall. cosb = (96-a²)/(20a) at (2). And a = 6 units. cosb = (96-36)/120 b = acos (½) b = 60° Therefore; Area ABD is; ½*6*(10+6)sin60 = 24√(3) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3141300

mathematics-question-and-solution_1750846480H0Nlqe.jpeg
Calculating Shaded Area. a = 4(4) a = 16 units. a is AB. b = a+4 b = 20 units. b is AC. It implies; 15²+20² = 7²+c² 225+400-49 = c² c = 24 units. c is CE. d = ½(c) d = 12 units. d is CD = DE. d' = atan(7/12) d' = 30.2564371635° d' is angle EDF. e² = 12²+7² e² = 144+49 e = √(193) units. e = 13.8924439894 units. e is DF. f = atan(15/20)+ atan(7/24) f = 53.1301023542° f is angle ACE. g² = 4²+12²-2*4*12cos53.1301023542 g = 10.1192885125 units. g is BD. (10.1192885125/sin53.1301023542) = (...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3140911

mathematics-question-and-solution_17508182146KhEFr.jpeg
Calculating Shaded Area. a² = 1²-(4k)² a = √(1-16k²) units. 1 ~ √(1-16k²) 4k ~ b Cross Multiply. b = 4k√(1-16k²) units. Again. 1 ~ √(1-16k²)  √(1-16k²) ~ c Cross Multiply. c = (1-16k²) units. d = 1-c d = 1-(1-16k²) d = 16k² units. e = 1-b e = (1-4k√(1-16k²)) units. Therefore; (5k)² = (16k²)²+(1-4k√(1-16k²))² 25k² = 256k⁴+1-8k√(1-16k²)+16k²(1-16k²) 25k² = 256k⁴+1-8k√(1-16k²)+16k²-256k⁴ 9k² = 1-8k√(1-16k²) 8k√(1-16k²) = 1-9k² 64k²(1-16k²) = 1-18k²+81k⁴ 64k²-1024k⁴ = 1-18k²+81k⁴...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3139969

mathematics-question-and-solution_1750728734rO2QE2.jpeg
a = x° b = (90-x)° R² = 6²+16²-2*6*16cosx R² = 292-192cosx  cosx = (292-R²)/192 --- (1). Notice. At (1). (292-R²) is adjacent. 192 is hypotenuse. Let c be opposite. c² = 192²-(292-R²)² c² = 36864-85264+584R²-R⁴ c = √(-R⁴+584R²-48400) units. It implies; sinx = √(-R⁴+584R²-48400)/192 --- (3). Again. R² = 10²+6²-2*10*6cos(90-x) R² = 136-120(cos90cosx+sin90sinx) R² = 136+120sinx --- (4). Substituting (3) in (4). R² = 136+120(√(-R⁴+584R²-48400)/192...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3138417

mathematics-question-and-solution_1750553879D3F0zw.jpeg
Let the side length of the square be x. a = (x-4) units. Calculating x. ½(x²) = ½*x(x-4)-10+30 x² = x(x-4)+40 x² = x²-4x+40 4x = 40 x = 10 units. Again, x is the side length of the square. Area Square is; x² = 10² = 100 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3134182

mathematics-question-and-solution_1750124879ljqoEY.jpeg
Notice. 10 m is the radius of the circle. a = 10-3 a = 7 m. sinb = (7/10) b = asin(7/10)° Calculating length AB. tanb = 10/(AB) AB = 10/(tanb) AB = 10/tan(asin(7/10)) AB = 10.2020406122 m. Or 7 ~ 3 10 ~ x Cross Multiply. 7x = 30 x = ⅐(30) m. x is length Be. It implies; y = 10+x y = 10+⅐(30) y = ⅐(100) m. y is length Bc Therefore; z² +10² = (⅐(100))² z² = (10000/49)-100 z² = (10000-4900)/49 z = √(5100/49) z = ⅐(10√(51)) m. z = 10.2020406122 m. z is the required length AB.
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm