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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3504946

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Calculating Area Green Region.a² = 10²+10²-2*10*10cos150a = 19.31851652578 cm.Where a is AF which is equal AE.(19.31851652578/sin150) = (10/sinb)b = 15°Where b is angle BAF.tan15 = c/10c = 2.67949192431 cm.It implies;Area Green Region is;Area square with side 10 cm - 2(area triangle with height 2.67949192431 cm and base 10 cm.= 10² - ½*2(10*2.67949192431)= 100-26.7949192431= 73.2050807569 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3504120

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Calculating Length PQ.a = atan(2)°b = 180-2ab = (180-2atan(2))°Where b is angle FBP.Notice;CQ = 5 cm.Calculating FP using sine rule.Let FP be c.(c/sin(180-2atan(2))) = (5/sin(atan(2)))c = 4.472135955 cm.Therefore;Length PQ is;CF-CQ-FP= √(10²+5²)-5-4.472135955 = (3√(5)-5) cm.= 1.7082039325 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3475634

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Sir Mike Ambrose is the author of the question.AB exactly is;= 16tan(3acos(8/9)) - 2√(17)= 2(8tan(3acos(8/9))-√(17)) cm.= 102.760478669 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3468425

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Calculating Area Red.a² = 6²+8²a = √(100)a = 10 cm.a is the side length of the square.6b+8b+10b = 8*624b = 48b = 2 cm.b is the radius of the inscribed circle.tanc = 6/8c = atan(3/4)°cosc = 2/dd = 2/cos(atan(3/4))d = 2.5 cm.e = 90-ce = atan(4/3)°tane = f/2.5(4/3) = f/2.5f = 2.5(4/3)f = ⅓(10) cm.f = 3.333 cm.g = (½(c)+90)°g = (0.5atan(3/4)+90)°h² = (8-2)²+2²h² = 40h = 2√(10) cm.j² = 10²+(2√(10))²-2*10*2√(10)cos(0.5atan(3/4)+90)j = 13.416407865 cm.(13.416407865/sin(0.5atan(3/4)+90)) = (2√(10)/sink...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3457050

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Sir Mike Ambrose is the author of the question.Calculating Shaded Area ÷ Green Area to 2 decimal places.Let the side of the regular pentagon be 1 unit.a = 108-90a = 18°b = 180-108-18b = 54°(1/sin54) = (c/sin108)c = 1.17557050458 units.(1/sin54) = (d/sin18)d = 0.38196601125 units.e = 1-de = 0.61803398875 units.f² = 0.61803398875²+1²-2*0.61803398875cos108f = 1.3281310261 units.(1.3281310261/sin108) = (1/sing)g = 45.73230144788°h = 180-108-45.73230144788h = 26.26769855212° I = 180-72-45.732301447...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3445673

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Calculating x.Let AD = y.x² = y²+32²-2*32*ycosax² = y²+1024-64ycosa --- (1).x² = y²+17²-2*17*ycosax² = y²+289+34ycosa --- (2).Calculating y.Equating (1) and (2).y²+1024-64ycosa = y²+289+34ycosa1024-64ycosa = 289+34ycosa1024-289 = 64ycosa+34ycosa735 = 98ycosaycosa = 735/98ycosa = 15/2cosa = 15/(2y) --- (3).cosa = y/32 --- (4).Equating (3) and (4).15/(2y) = y/322y² = 15*32y² = 16*15y = 4√(15) units.It implies, x, length AB = AC is;32² = x²+(4√(15))²1024 = x²+240x² = 1024-240x² = 784x = √(784)x =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3440998

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Calculating x, length AD.Let AB = AC = a.cosb = x/32 --- (1).a² = 32²+x²-2*32*xcosba² = 1024+x²-64xcosb --- (2).a² = 23²+x²+2*23*xcosba² = 529+x²+46xcosb --- (3).Equating (2) and (3).1024+x²-64xcosb = 529+x²+46xcosb1024-64xcosb = 529+46xcosb495 = 110xcosbcosb = 495/(110x) --- (4).Therefore, x, length AD is;Equating (1) and (4).x/32 = 495/(110x)110x² = 32*495x² = (32*495)/110x² = 144x = 12 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3436640

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Calculating R, radius of the circle.Let theta be x.x+x+x = 360x = 120°a² = 6²+5²-2*5*6cos120a² = 61+30a = √(91) units.(√(91)/sin120) = (6/sinb)b = 33.0044915989°c² = 5²+15²-2*5*15cos120c² = 250+75c = √(325)c = 5√(13) units.(5√(13)/sin120) = (15/sind)d = 46.102113752°e = b+de = 33.0044915989+46.102113752e = 79.1066053509°f² = 6²+15²-2*6*15cos120f² = 261+90f = √(351)f = 3√(39) units.g = ½(f)g = 1.5√(39) units.Therefore, R, radius of the circle is;sin79.1066053509 = (1.5√(39))/RR = (1.5√(39))/sin7...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3434548

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Calculating Area Triangle AED.Let x be CD.Figuring an equilateral triangle OCD considering the strategic given two equal angles, 60°.a = (x-8) units.a is DE.b = (x-10) units.b is OA.cos60 = c/8c = 4 units.c is BC.d = (x-4) units.d is OB.Let AB = AE = y.y² = (x-10)²+(x-4)²-2(x-4)(x-10)cos60y² = x²-20x+100+x²-8x+16-(x²-14x+40)y² = 2x²-28x+116-x²+14x-40y² = x²-14x+76y = √(x²-14x+76) units.Therefore, calculating x, length CD.√(x²-14x+76)² = 10²+(x-8)²-2*10(x-8)cos60x²-14x+76 = 100+x²-16x+64-10x+80-...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3424247

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Sir Mike Ambrose is the author of the question.a² = 10²+16²-2*10*16cos120a = 2√(129) units.Where a is length AC.(3√(129)/sin120) = (16/sinb)b = 37.58908946897°c = 90-bc = 52.41091053103° d = 60-bd = 22.41091053103°e = 90-de = 67.58908946897° f = 90-60f = 30°cos37.58908946897 = g/10g = 7.92405815693 units.i = 30+37.58908946897i = 67.58908946897°tan67.58908946897 = j/7.92405815693j = 19.2148198619 units.Where j is the radius of the arc.sin67.58908946897 = 19.2148198619/kk = 20.78460969082 units.l...

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Please, highlight and open/browse the links below to view videos of our teaching and learning activities. Thank you. Video 1. Class with Adesuwa (year 5) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid02VGXZkxZYksDaBSZXhbkir8GKETEiU2fCQobAVZE4Yv84HRaQ3NL1XvAMTRTxsNs3l/?app=fbl Video 2. Class with Zino and Ruemu (year 4) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid038EyeWYY8Du4XgbEb7mbz33DS7XAvYWjXTwrE6HRfC4qpFTqCX6YVFYmnCeDBfEWHl/?app=fbl Video 3. Class with A...
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