By OnlineEdumath   |  6th November, 2024
Calculating Green Area. a = 2*4 a = 8 units. a is the radius of the ascribed quarter circle. b²+4² = 8² b² = 64-16 b = √(48) b = 4√(3) units. tanc = 4√(3)/4 c = atan(√(3))° c = 60°...
By OnlineEdumath   |  6th November, 2024
Inscribed semi circle radius is 4 cm. Inscribed quarter circle radius is 8 cm. tana = 4/8 a = atan(½)° b = 2a b = 2atan(½)° c = 180-b c = 2atan(2)° Blue Area is; Area sector wi...
By OnlineEdumath   |  5th November, 2024
2^(x+1)+2^(x-1) = 320 Let 2^(x) be p. It implies; 2p+½(p) = 320 ½(5p) = 320 5p = 640 p = 128 And  p = 2^(x) Calculating x. 2^(x) = 128 2^(x) = 2⁷ x = 7
By OnlineEdumath   |  5th November, 2024
Let b be 1 unit. a = 50° b = 40° a and b are the two interior complementary angles or acute angles of the small right-angled triangle with hypotenuse b. sin50 = c/b c = sin50 c = 0.766044...
By OnlineEdumath   |  4th November, 2024
Calculating angle x. Let 1 be the base of the ascribed isosceles triangle. a = 180-39-2(27) a = 141-54 a = 87° (1/sin87) = (b/sin(2*27)) b = 0.8101272456 units. c = 180-27-15-39 c =...
By OnlineEdumath   |  4th November, 2024
Let AB be a. b = (a-2) units. c = ½(a) units. c is BD. d = c-2 d = ½(a)-2 d = ½(a-4) units. It implies; 2 - (a-2) ½(a-4) - 2 Cross Multiply. 4 = ½(a-4)(a-2) 8 = a²-6a+8 a...
By OnlineEdumath   |  3rd November, 2024
Let 1 be the side length of the ascribed regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the ascribed regular hexagon. b² = 1²+1²-2*1*1cos120 b = 1.7320508076 un...
By OnlineEdumath   |  3rd November, 2024
Calculating Alpha. Let it be a. Let b be the radius of the ascribed quarter circle. c = (b-√(2)) units. d = (b-2√(2)) units. It implies, observing similar plane shape (right-angled)...
By OnlineEdumath   |  2nd November, 2024
Calculating angle x. Let AR be 1 unit. a = 180-24-15 a = 180-39 a = 141° a is angle ARK. (1/sin15) = (b/sin141) b = 2.4315072749 units. b is AK. c = 180-12-6 c = 180-18 c = 162°...
By OnlineEdumath   |  2nd November, 2024
Sir Mike Ambrose is the author of the question. Calculating the equation of the curve. y-b=a(x-4)² ----- (1) At coordinate (8, 0) -b=16a Therefore; a = -b/16 Sub. a in (1) to get...
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