Mathematics Question and Solution
Calculating the ascribed square area.
Let x be the square side length.
a = 6+7
a = 13 units.
b²+x² = 13²
b = √(169-x²) units.
Calculating x², area of the ascribed square..
√(169-x²) ~ 6
13 ~ x
Cross Multiply.
x√(169-x²) = 78
x²(169-x²) = 6084
x⁴-169x²+6084 = 0
(x²-½(169))² = -6084+(-½*169)²
(x²-½(169))² = ¼(-24336+169²)
(x²-½(169))² = ¼(4225)
x² = ½√(169)±½√(4225)
x² = ½(169)±½(65)
x² = ½(169±65)
It implies;
x² ≠ ½(169-65) ≠ ½(104) ≠ 52 square units.
x² = ½(169+65) = ½(234) = 117 square units.
Where x² is the area of the ascribed square.
