Mathematics Question and Solution
Let the side length of the ascribed square be 2 units.
Area ascribed square is;
2²
= 4 square units.
a² = 2²+1²
a = √(5) units.
tanb = 2/1
b = atan(2)°
c = 180-2b
c = (180-2atan(2))°
cos(180-2atan(2)) = d/√(5)
d = 1.3416407865 units.
Area Triangle Orange is;
0.5*1.3416407865√(5)sin(180-2atan(2))
= 1.2 square units.
= (6/5) square units.
It implies;
Fraction of the square that is orange is;
Area Orange ÷ Area Square
= (6/5)÷4
= 6/20
= 3/10
