By OnlineEdumath   |  17th August, 2024
Let a be the base of the blue inscribed triangle. b = 4-1-a b = (3-a) units. c² = 2(1)² c = √(2) units. d² = 2(4)² d = 4√(2) units. e = d-c e = 3√(2) units. f² = a²+4² f = √(a²+...
By OnlineEdumath   |  17th August, 2024
Calculating blue inscribed half circle area. Let the radius of the blue inscribed half circle be a. 20² = 2b² b² = 200 b = √(200) b = 10√(2) units. c²+(0.5b)² = a² c² = a²-(5√(2))² c...
By OnlineEdumath   |  17th August, 2024
x = 180-2(70) x = 180-140 x = 40°
By OnlineEdumath   |  17th August, 2024
Sir Mike Ambrose is the author of the question. Area purple exactly in decimal is; Area triangle with height 5cm and base 7.5cm - Area triangle with height 3cm and base 7.5cm - Area triangle wi...
By OnlineEdumath   |  16th August, 2024
Sir Mike Ambrose is the author of the question. Notice; The single length of the square is equal the single side length of half the regular hexagon. Let it be 2 units. Therefore area squa...
By OnlineEdumath   |  16th August, 2024
a = 8+10 a = 18 units. a is GK. b² = 18²-9² b = √(243) b = 9√(3) units. b is DK. tanc = 9√(3)/9 c = atan(√(3)) c = 60° d² = 9²+8²-2*8*9cos60 d = √(73) units. d = 8.5440037453 unit...
By OnlineEdumath   |  16th August, 2024
Sir Mike Ambrose is the author of the question. Let the bigger regular pentagon side length be 1 unit. a = √(2-2cos180) a = 1.61803398875 units. b = sin36/sin108 b = 0.61803398875 units....
By OnlineEdumath   |  15th August, 2024
Let the two congruent lengths be a each. 21² = a²+b²+2abcos135 441 = a²+b²+√(2)ab --- (1) 14² = a²+b²-2abcos45 196 = a²+b²-√(2)ab --- (2) Adding (1) to (2). 637 = 2a²+2b²  b² = ½(637...
By OnlineEdumath   |  15th August, 2024
Area orange exactly in fraction is: Area triangle with height 5√(3) cm and base 5 cm. = ½(5√(3)*5) = ½(25√(3)) cm² = 21.6506350946 cm²
By OnlineEdumath   |  15th August, 2024
a = ½(5) a = 2.5 units. a is the radius of the inscribed half circle. tanb = 2.5/5 b = atan(1/2)° tan(atan(0.5)) = r/c ½ = r/c c = 2r units. d = 5-c d = (5-2r) units. e = (2.5-r)...
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