By OnlineEdumath   |  3rd September, 2024
(9^(p)*81)-9^(p) = 240 Let 9^(p) = a. 81a-a = 240 80a = 240 a = 3 It implies; 9^(p) = 3 p = ½ Therefore; (8p)^(p) is; √(8*½) = √(4) = 2
By OnlineEdumath   |  3rd September, 2024
a² = 6²+9²-2*6*9cos60 a = 7.9372539332 units. (7.9372539332/sin60) = (6/sinb) b = 40.8933946491° (7.9372539332/sin120) = (6/sinc) c = 40.8933946491° d = c+b d = 81.7867892983° e = 1...
By OnlineEdumath   |  3rd September, 2024
Calculating area of the ascribed square and area of the inscribed blue triangle. a²+8² = 10² a = 6 units. 6 - 8 b - x Cross Multiply. 8b = 6x b = ¼(3x) units  c²+x² = 8² c = √(64...
By OnlineEdumath   |  3rd September, 2024
Let AB be 1 unit. a = 180-18-36 a = 126° a is angle APB. (1/sin126) = (b/sin18) b = 0.3819660113 units  b is BP. c = 180-(12+18)-(36+36) c = 180-102 c = 78° c is angle ACB. (1/s...
By OnlineEdumath   |  3rd September, 2024
Notice. The complete plane shape is half a circle with radius 8 cm. Area green is; Area semi circle with radius 8cm - 2(area quarter circle with radius 8 cm - area triangle with height and...
By OnlineEdumath   |  2nd September, 2024
Calculating area of the inscribed red circle. Let the bigger circle radius be a. Let the big circle radius be b. It implies; a+b = 6 --- (1). ½(b²)+½(a²)+14 = 6*a b²+a²+28 = 12a ---...
By OnlineEdumath   |  2nd September, 2024
a = ⅐(360)° a is the interior angle of each of the congruent 7 sectors. Let the radius of the ascribed circle be 1 unit. Area ascribed circle is; π(1²) = π square units. c = (1-b) uni...
By OnlineEdumath   |  2nd September, 2024
Calculating x. a²+4² = 5² a² = 25-16 a = 3 units. Therefore; 3*(x+5) = 4*(2x-5) 3x+15 = 8x-20 5x = 35 x = 7 units. It implies; b = 3+x+5 And x = 7 units. b = 3+7+5 b = 15 uni...
By OnlineEdumath   |  2nd September, 2024
Calculating the required angle, x. a = ⅐*180(7-2) a = ⅐(900) a is the single interior angle of the regular heptagon. It implies, the required angle, x is; Notice. Length IC is paralle...
By OnlineEdumath   |  2nd September, 2024
Calculating shaded area. Let the equal lengths of the ascribed trapezoid be a. Calculating a. a² = 6²+(18-a)² 0 = 36+324-36a 36a = 360 a = 10 units. Therefore, shaded area is; ½(1...
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