Sir Mike Ambrose is the author of the question.
Calculating letter k considering yellow area (trapezoid).
It implies;
Half the sum of two parallel length (54+4k²)/9 units and (54+10k²)/9 units...
Shaded area is;
Area semi circle with radius 7cm + Area rectangle with length 14 cm and width 7 cm - Area semi circle with radius 7cm.
= ½(49π) + (14*7) - ½(49π)
= 98 cm²
Or
Shaded Area...
Let a ber the radius of each of the two congruent circles.
b = (a+29) units.
b is the side length of the square.
c² = 2*29²
c² = 1682
c = 29√(2) units.
Calculating a.
It implies;...
Calculating green area.
a² = 2²+2²
a = √(8)
a = 2√(2) units.
sin30 = b/a
½ = b/(2√(2))
b = √(2) units.
c²+b² = a²
c²+√(2)² = (2√(2))²
c² = 8-2
c = √(6) units.
Area green is;
(...
Let the base of the quadrilateral be 1 unit.
a = -54-18+180
a = 108°
(1/sin108) = ((b/sin18)
b = 0.3249196962 units.
Therefore, area B is;
0.5*1*0.3249196962sin54
= 0.131432778 squar...
Let c be the radius of the ascribed half circle.
d² = 2c²
d = √(2)c cm.
d is the diameter of the inscribed half circle.
e = ½(d)
e = ½(√(2)c) cm.
e is the radius of the inscribed half circ...
13² = 20²+11²-2*20*11cosa
169 = 521-440cosa
440cosa = 521-169
cosa = 352/440
a = 36.8698976458°
(13/sin36.8698976458) = (11/sinb)
b = 30.5102374061°
c = 180-a-b
c = 112.6198649481°
d...
a*3 = 2*6
a = 12/3
a = 4 units.
b = ½(a+3)
b = 3.5 units.
c = ½(2+6)
c = 4 units.
d = c-2
d = 2 units.
It implies, e, radius of the circle is;
e² = 3.5²+2²
e = √(16.25)
e = ½√...
Sir Mike Ambrose is the author of the question.
Let BC be 1 unit.
Therefore;
AB = 2 units.
Area ACDE is;
3²
= 9 square units.
Area purple is;
Area triangle with height 1.2393136...
Let the two equal lengths be a.
b = (4+a) units.
Calculating a.
20² = (4+a)²+a²
400 = 16+8a+2a²
a²+4a+8-200 = 0
a²+4a-192 = 0
(a+2)² = 192+(2²)
a = -2±√(196)
a = -2±14
It implies;
a...
