By OnlineEdumath   |  2nd June, 2024
tana = 5/8 a = atan(5/8)° b = atan(8/5)° c = 180-45-a c = (135-atan(5/8))° d = (135-atan(8/5))° (e/sin(atan(8/5))) = (3/sin(135-atan(8/5))) e = 2.6108558075 units. (f/sin(atan(5/8...
By OnlineEdumath   |  1st June, 2024
a² = 24²+7² a = 25 units. a is DF. b²+20² = a² b² = 25²-20² b = 15 units. b is EF. tanc = 7/24 c = atan(7/24)° c is angle CED. tand = 15/20 d = atan(3/4)° d is EDF. e = 180-c-d...
By OnlineEdumath   |  1st June, 2024
√(x-2)-√(x+3) = 1 x-2=(1+√(x+3))² x-2=1+2√(x+3)+x+3 -6=2√(x+3) -3=√(x+3) 9=x+3 x=6. Checking accuracy. √(6-2)-√(6+3)=? √(4)-√(9)=? ±2-±3=? ±2+3=? +2+3≠1 Therefore; -2+3=1
By OnlineEdumath   |  1st June, 2024
Let the single side length of the ascribed square be 2 unit. Therefore area of the ascribed square is; 4 square unit. Calculating shaded area (area yellow). It will be; Area square of single sid...
By OnlineEdumath   |  1st June, 2024
Calculating Area Red/Area Yellow. Let R, radius of the equal circles be 1 unit. Area Yellow is; 2(2(area sector with radius 1 unit and angle 60°) - area regular triangle with side length 1...
By OnlineEdumath   |  1st June, 2024
Notice! AC = 7+7 AC = 14 units. It implies; 14² = 2a² a² = ½(196) a = √(98) a = 7√(2) units. a is the side length of square ABCD. Therefore, shaded area yellow is; Area square w...
By OnlineEdumath   |  1st June, 2024
sin30 = 10/a a = 20 units. a is the side length of the square. sin30 = b/10 b = 5 units. Therefore; Area Yellow is; Area triangle with height 20 units and base 5 units. = ½*20*5...
By OnlineEdumath   |  1st June, 2024
a² = 3²+5²-2*3*5cos60 a = √(19) units. a = 4.3588989435 units. a is AC. b² = 2²+1²-2*2*1cos60 b = √(3) units. b = 1.7320508076 units. b is CD. (√(19)/sin120) = (√(3)/sinc) c = 20.12830...
By OnlineEdumath   |  1st June, 2024
Calculating x. (a+30)*x = (30+15)(30+15) x = 45²/(a+30) --- (1). a*x = 15*15 a = 225/x --- (2). Therefore, Substituting (2) in (1) to get x. x = 45²/((225/x)+30) x = 2025÷(225+30x)/x...
By OnlineEdumath   |  1st June, 2024
5² = 2a² a² = ½(25) a = √(½(25)) cm. a = √(12.5) cm. b = 5-a b = (5-√(½(25))) cm. b = (5-√(12.5)) cm. It implies, blue area is; ½(b²) = ½(5-√(½(25)))² = ½(5-√(12.5))² = ½(25-10√(12...
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