7² = 3²+8²-2*3*8cosa
48cosa = 9+64-49
a = acos((9+64-49)/48)
a = 60°
Calculating b, radius of the inscribed circle.
3b+8b+7xb = 3*8sin60
18b = 12√(3)
3b = 2√(3)
b = ⅔√(3) units.
b = 1.1547005384 units.
tan30 = b/c
c = 1.1547005384/tan30
c = 2 units.
Therefore, length x is?
x² = 2²+2²-2*2*2cos60
x² = 8-8cos60
x² = 8-4
x = √(4)
x = 2 units.
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