By OnlineEdumath   |  8th September, 2024
Let a be the radius of the quarter circle. b = x° c = (45-x)° It implies; sinx = 1/a --- (1). sin(45-x) = 2/a --- (2). At (1). a = 1/sinx --- (3). Substituting (3) in (2)....
By OnlineEdumath   |  8th September, 2024
Let the single side length of the equilateral hexagon be 1 unit. Therefore; Area blue is; Area triangle with two sides 1 unit each, and angle 120° + Area triangle with base ½ units and hei...
By OnlineEdumath   |  8th September, 2024
Let a be 1 unit. d = ⅙*180(6-2) d = 120° d is the single interior angle of the regular hexagon. cos60 = e/1 e = 0.5 units. f = a+2e f = 2 units. f is CF. g² = 0.5²+2²-2*0.5*2cos60...
By OnlineEdumath   |  8th September, 2024
a = x+1+2 a = (x+3) units. a is BC. b = 4+2 b = 6 units. Calculating x. (2x)² = (x+3)²+6² 4x² = x²+6x+9+36 3x²-6x-45 = 0 x²-2x-15 = 0 x²-5x+3x-15 = 0 x(x-5)+3(x-5) = 0 (x-5)(x+3)...
By OnlineEdumath   |  8th September, 2024
½*a*b = 10 a = (20/b) cm. a is CD. b is OD. b² - 30 (20/b)² - 10 Cross Multiply. 10b² = 12000/b² 10b⁴ = 12000 b⁴ = 1200 b⁴ = 1200 b² = √(1200) b² = 20√(3) b = √(20√(3)) b = 5.885...
By OnlineEdumath   |  7th September, 2024
a = 2+3 a = 5 units. b²+3² = a² b² = 25-9 b = √(16) b = 4 units. Let x be the radius of the ascribed semi circle. c = (2-(x-4)) units. c = (6-x) units. d² = (6-x)²+3² d² = 36-12x+...
By OnlineEdumath   |  7th September, 2024
Shaded/Area Blue is; 2(area sector with radius 4 units and angle (180-2atan(½))° - area triangle with two side 4 units respectively, and angle (180-2atan(½))°) + 2(area sector with radius 2 unit...
By OnlineEdumath   |  7th September, 2024
8^(x)+4^(x) = 36 2^(3x)+2^(2x) = 36 Let 2^(x) be p. Therefore; p³+p² = 36 p = 3 And p = 2^(x) 2^(x) = 3 x = log3/log2 x = 1.5849625007 Checking Accuracy. 8^(x)+4^(x) = 36...
By OnlineEdumath   |  7th September, 2024
a = ⅕*180(5-2) a = 108° a is the single interior angle of the ascribed regular pentagon. b = 360-2a-90 b = 360-306 b = 54° c = 90-b c = 36° d = 180-2c d = 108° Notice. The insc...
By OnlineEdumath   |  7th September, 2024
Let a be the radius of the inscribed half circle. b = (a-1) units. It implies, calculating a. a² = (a-1)²+5² a² = a²-2a+1+25 2a = 26 a = 13 units. Again, a is the radius of the inscrib...
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