Mathematics Question and Solution
Let AB be 1 unit.
a = 180-18-36
a = 126°
a is angle APB.
(1/sin126) = (b/sin18)
b = 0.3819660113 units
b is BP.
c = 180-(12+18)-(36+36)
c = 180-102
c = 78°
c is angle ACB.
(1/sin78) = (d/sin30)
d = 0.5111702974 units.
d is BC.
e² = 0.5111702974²+0.3819660113²-2*0.5111702974*0.3819660113cos36
e = 0.3021133709 units.
e is CP.
Therefore, the required angle, x is;
(0.3021133709/sin36) = (0.3819660113/sinx)
x = asin(0.7431448256)
x = 48°
