Calculating AB, the diameter of the circle.
Let it be x.
Sin(atan(⅓)) = √(6²+2²)/x
Sin(atan(⅓)) = √(40)/x
x = √(40)/sin(atan(⅓))
x = 20 cm.
x is AB.
Therefore length AC is;
AB - 2
AC = 20 - 2
AC = 18 cm.
Or
Let AC be x.
2 ~ 6
6 ~ x
Cross Multiply.
2/6 = 6/x
2x = 36
x = 18 cm.
AC = 18 cm.
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