Mathematics Question and Solution
1. The Right-angled Triangle.
Calculating length x.
a = 9+6
a = 15 cm.
a is the height of the ascribed right-angled triangle.
17 cm is the hypotenuse of the ascribed right-angled triangle.
b²+15² = 17²
b² = 17²-15²
b² = 289-225
b = √(64)
b = 8 cm.
b is the base of the ascribed right-angled triangle.
It implies;
Calculating s.
s² = 6²+8²
s² = 36+64
s² = 100
s = √(100)
s = 10 cm.
2. The Half Circle.
Calculating A.
Notice.
4 cm is the radius of the half circle.
a = 2*4
a = 8 cm.
Or
a = 4+4
a = 8 cm.
a is the diameter of the half circle.
It implies;
Calculating A, Observing Pythagoras Rule.
A²+A² = 8²
2A² = 64
A² = ½(64)
A² = 32
A = √(32)
A = √(16)*√(2)
A = 4√(2) cm.
Therefore;
B is;
B = A+A
B = 2A
And A = 4√(2) cm.
B = 2*4√(2)
B = 8√(2) cm.
